Output original image fourier transform filter with

Info icon This preview shows pages 3–5. Sign up to view the full content.

Output: Original Image Fourier Transform Filter with 10 cutoff Frequency Filtered Image Filter with 50 cutoff Frequency Filtered Image Filter with 100 cutoff Frequency Filtered Image T ASK -2: Butterworth Low Pass Filter Code: im=imread('fig.png'); im=rgb2gray(im); fr2=fft2(im2double(im)); fr=fftshift(fr2); [r c]=size(im2double(im)); fitr=zeros(r,c); [u,v]=meshgrid(-(r/2-1):r/2,-(c/2-1):c/2); Do=10; n=20; blpfh=zeros(r,c); blpfh=1./(1+(sqrt(u.^2+v.^2)./Do).^(2*n)); fid=fr.*blpfh; ifid=ifftshift(fid); ifid=ifft2(ifid); subplot(4,2,1),imshow(im),title('Original Image'); subplot(4,2,2),imshow(fr2),title('Fourier Transform'); subplot(4,2,3),imshow(blpfh),title('Filter with 10 cutoff Frequency'); subplot(4,2,4),imshow(ifid),title('Filtered Image'); Do=50; n=20; blpfh=zeros(r,c); blpfh=1./(1+(sqrt(u.^2+v.^2)./Do).^(2*n)); fid=fr.*blpfh; ifid=ifftshift(fid); ifid=ifft2(ifid); subplot(4,2,5),imshow(blpfh),title('Filter with 50 cutoff Frequency');
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

subplot(4,2,6),imshow(ifid),title('Filtered Image'); Do=100; n=20; blpfh=zeros(r,c); blpfh=1./(1+(sqrt(u.^2+v.^2)./Do).^(2*n)); fid=fr.*blpfh; ifid=ifftshift(fid); ifid=ifft2(ifid); subplot(4,2,7),imshow(blpfh),title('Filter with 100 cutoff Frequency'); subplot(4,2,8),imshow(ifid),title('Filtered Image'); Output: Original Image Fourier Transform Filter with 10 cutoff Frequency Filtered Image Filter with 50 cutoff Frequency Filtered Image Filter with 100 cutoff Frequency Filtered Image Gaussian Low Pass Filter Code: clc; clear all; close all; im=imread('fig.png'); img=rgb2gray(im); fr2=fft2(im2double(img)); fr=fftshift(fr2); [m n]=size(im2double(img));
Image of page 4
Image of page 5
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern