# A 5 x 2 550 x 5000 5 x 2 110 x 1000 5 x 10 x 100 x 10

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a) 0 =− 5 x 2 + 550 x 5000 0 =− 5 ( x 2 110 x + 1000 ) 0 ± 5 ( x 10 )( x 100 ) x = 10, x = 100 In order for the company to break even or have an end result profit of \$0, the company would have to spend either \$10,000 or \$100,000 on advertising. b) The graph of the corresponding relation shows the x-intercepts, which are break even points where the company will have \$0 profit from advertising spending. 18. Distance Speed Time Tokyo to Bangkok 4800 x T = 4800 x Bangkok to Tokyo 4800 x 200 T = 4800 x 200 ( 4800 x ) + 2 = 4800 ( x 200 )

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( 4800 x ) x ( x 200 ) + 2 x ( x 200 ) =( 4800 ( x 200 ) x ( x 200 ) ) 4800 x 960000 + 2 x 2 400 x = 4800 x 2 x 2 400 x 960000 = 0 2 ( x 800 ) ( x + 600 ) = 0 x = 800, x =− 600 The Jet speed from Bangkok to Tokyo was 800 km/h. 19. ∙x = 2 ± 5 , ( 2,10 ) x = 2 ± 5 x =( 2 + 5 )( 2 5 ) x 2 ¿ 2 + 10 y = a ¿ x = 2, y = 10 y = a ( x 2 + 5 )( x 2 5 ) 10 = a ( 2 2 + 5 )( 2 2 5 ) 10 = a ( 5 )(− 5 ) 10 = a (− 5 ) 10 =− 5 a a =− 2 x 2 ¿ 2 + 10 y =− 2 ¿ y =− 2 ( x 2 ) ( x 2 ) + 10 y =− 2 ( x 2 2 x 2 x + 4 ) + 10 y =− 2 ( x 2 4 x + 4 ) + 10 y =− 2 x 2 8 x 8 + 10 y =− 2 x 2 8 x + 2 ∙x = 1 3 , x =− 4, ( 1,5 ) 3 x = 1, x =− 4 x 1 ¿ 2 + 5 y = a ¿ x = 1, y = 5
y = a ( 3 x + 1 )( x 4 ) 5 = a ( 3 ( 1 ) + 1 )( 1 4 ) 5 = a ( 4 )(− 3 ) 5 = a (− 12 ) 5 =− 12 a a = 5 12 x 1 ¿ 2 + 5 y = 5 12 ¿ y = 5 12 ( x 1 ) ( x 1 ) + 5 y = 5 12 ( x 2 x x + 1 ) + 5 y = 5 12 ( x 2 2 x + 1 ) + 5 y = 5 12 x 2 + 10 12 x 5 12 + 60 12 y = 5 12 x 2 + 10 12 x + 55 12 y = 1 12 (− 5 x 2 + 10 x + 55 ) 20. a)

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y = 3 x + 5 y = 3 x 2 2 x 4 3 x + 5 = 3 x 2 2 x 4 0 = 3 x 2 3 x 2 x 5 4 3 x 2 5 x 9 = 0 b 2 4 ac =− 5 2 4 ( 3 )(− 9 ) b 2 4 ac = 25 + 108 b 2 4 ac = 133 There are 2 solutions. b) y = b 2 4 ac 2 a y = 5 ± 5 2 4 ( 3 )(− 9 ) 2 ( 3 ) y = ¿ 5 ± 25 + 108 6 y = 5 ± 133 6 The points of intersection are y = 5 + 133 6 , y = 5 133 6
• Spring '18
• Leigh
• Math, Quadratic equation, Continuous function, Inverse function, \$10,000, \$0, b2−4 ac

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