# The thin lens equation is 1 p 1 q 1 f let f 1 6 4 m f

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Note:After sketching the ray diagramabove and using the positions on the scale,we havef1= (10 m)-(3.6 m)= 6.4 m,or= (16.4 m)-(10 m)= 6.4 mp2=q1= (27.7778 m)-(10 m)= 17.7778 mf2= (39.8 m)-(33.9 m)= 5.9 m,or= (45.7 m)-(39.8 m)= 5.9 m,andq2= (51.3858 m)-(39.8 m)= 11.5858 m.Solution:q1=11f1-1p1=116.4 m-110 m=17.7778 m.
second lens?
The thin lens equation is1p+1q=1f.032 (part 2 of 4) 10.0 pointsWhat is the magnification of the first image?At what distance is the second image from the
hatch (heh595) – reflection refraction imaging HW – yeazell – (55740)11Whichof the glass lensesabove,whenplaced in air, will cause rays of light (par-allel to the central axis) toconverge?
034 (part 4 of 4) 10.0 pointsWhat is the magnification of the final image,when compared to the initial object?8.A and E
hatch (heh595) – reflection refraction imaging HW – yeazell – (55740)12E:R1<0 andR2<0, but|R1|>|R2|,=f >0,therefore convergent.M:R1>0 andR2>0, but|R1|=|R2|,=f=,therefore neither convergentor divergent.Thus, lenses B, K, and E are convergentlenses and Lenses A and C are divergent.Alternate (Elegant) Solution:Converging Lens:The glass is thicker onthe axis than at the edge. B, K, and E satisfythese conditions for a converging lens (f >0).Diverging Lens:The glass is thinner onthe axis than at the edge.A and C satisfythese conditions for a diverging lens (f <0).Neutral Lens:The glass has a constantthickness.Rays of light are parallel to thecentral axis on both sides of the lens.Msatisfy this conditions for a non-focusing lens(f=).036 (part 1 of 3) 10.0 pointsA thin lens has a crescent shape, which isdefined by two spherical surfacesAandB.The radius of the surfaceAis|RA|= 3a ,and of surfaceBis|RB|=a .The lens issubmerged in a medium.ABa3aOCACB

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