Computer Assignment 6 Solution
EE114, Winter 2014
4/9
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Figure 3 FT coefficients magnitude, reduced to [-128:127]
Typing
im_128 = real(ifft2(ft_128));
imagesc(im_128);
axis square;
PSNR(im, im_128)
yields the result in Figure 4 and a
PSNR = 31.2383
.

EE114, Winter 2014
Computer Assignment 6 Solution
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Figure 4 Bridge, reconstructed from [-128,127]
2.3
Task c Reduce to [-64:63]
Typing
ft_64
= ReduceFT(ft, 64);
sft_64 = ScaleFTAmp(ft_64);
imagesc(sft_64); colormap(gray);
axis square;
yields the result in Figure 5.

Computer Assignment 6 Solution
EE114, Winter 2014
6/9
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Figure 5 FT coefficients, reduced to [-64:63]
Typing
im_64 = real(ifft2(ft_64));
imagesc(im_64);
axis square;
PSNR(im, im_64)
yields the result in Figure 6 and a
PSNR = 26.7170
.

EE114, Winter 2014
Computer Assignment 6 Solution
________________________________________________________________________
7/9
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Figure 6 Bridge, reconstructed from [-64,63]
2.4
Task c Reduce to [-32:31]
Typing
ft_32
= ReduceFT(ft, 32);
sft_32 = ScaleFTAmp(ft_32);
imagesc(sft_32); colormap(gray);
axis square;
yields the result in Figure 7.

Computer Assignment 6 Solution
EE114, Winter 2014
8/9
50
100
150
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250
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350
400
450
500
50
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Figure 7 FT coefficients magnitude, reduced to [-32:31]
Typing
im_32 = real(ifft2(ft_32));
imagesc(im_32);
axis square;
PSNR(im, im_32)
yields the result in Figure 8 and a
PSNR = 24.1756
.

EE114, Winter 2014
Computer Assignment 6 Solution
________________________________________________________________________
9/9
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Figure 8 Bridge, reconstructed from [-32:31]

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- Spring '11
- VanSchaar
- Digital Signal Processing, Signal Processing, Harshad number, Self number, Hebrew numerals, FT coefficients