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20. B. The PIV for each diode in a center-tapped full-wave rectifier is twice the peak output voltage plus one diode drop. 22. A. A capacitor-input filter provides a dc output approximately equal to the peak of its rectified input voltage. 24. C. The formula Vr(pp)=(1/fRLC)Vp(rect)=(1/ can be used to find that the voltage is 5V.26. D. The line regulations specifies how much change occurs in the output voltage for a given change inthe input voltage. 28. D. The maximum voltage across a diode when it is powered by a sinusoidal voltage is 10V. 30. B. The RMS voltage is changed to peak voltage to reveal that it is 169.7V peak input, so less the diode drop the output would be 169V.32. B. A voltage tripler’s output is found by the formula 3Vpchanging the RMS value to peak and then multiplying by 3 gives us 50.9V34. B. When a diode is open you will get an OL or out of range indication for both the forward and reverse bias conditions.36. C. The open diode prevents current through RLduring half of the input voltage cycle resulting in a half wave rectification with double the ripple voltage. Problems
5. a. Reverse biasb. Forward biasc. Forward biasd. Forward bias6. a. -.37Vb. .7Vc. .7Vd. .7V7. a. -3Vb. 0Vc. 0Vd. 0V8. a. -2.99Vb. 2.44V, 99.99Vc. 740.6mV, 29.99Vd. 709.3mV, 9.99V