0431277172568 1001679 35038284732 sum error

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% error (diameter) = (Standard Deviation/Average Diameter)×100=(0.043127717/2.568) ×100=1.679 %error(volume)=(%error(diameter) ×3)=5.038284732 Sum% error= %error(mass)+%error(volume)=5.088234782
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Discussion: The density of the ball was measured to be 1.1289. It was determined as accurately as possible by following the above listed procedures and following them. The error for the entire experiment was also found as 0.0451. The experiment was found to be a success as the error of 0.0451 is less than 5% of the actual value of the density. Error: Mass error: This is the possible error taken into consideration for the mass, as the mass didn’t have enough values to be evaluated with standard deviation. This is a measurement error. It was estimated to the hundredth of a gram. Diameter measurement error: This is affected by the fact that the ball’s diameter varied with every measurement using the vernier callipers. There are different values for measurement. The ball wasn’t solid: The ball’s nature makes it possible for there to be variance in the diameter of the ball. Air Resistance when measuring mass: Air resistance affects the values of the mass of the ball being measured. Procedure Questions: 1. The object floats or sinks depending majorly on its density. If the objects density is greater than 1 i.e. (density of water), then it will sink. If its density is less than 1, it will float 2. The ball sank. The ball behave as it should have given my predicted density. The error in the density was small enough to be ignored. 3. The % error was less than 5%, hence the experiment was a success. Conclusion: The error in the density was negligible and the ball’s density was greater than 1.0, hence the ball sunk below the water surface. We calculate the volume and mass of the ball considering its errors and found its density.
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PHYSICS 1 Lab Report Osagie Obaze 1/13/2012
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