So the solution is x 2 2 b y 4 3 b a 3a dne 1 because

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1“Does Not Exist”1
5.(a) FALSE. (AB)T=BTAT.(b) FALSE. IfAB=ACandAis invertible, thenB=C.(c) FALSE. It is true for anyanegationslash= 0,bnegationslash= 0, andcnegationslash= 0.(d) FALSE. It’sAR2+3R4−−−−−−−→A.6.

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