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Substances used included Ba(IO3)₂at various temperatures, as well as 1.0 M HCl, 0.50 M KI, and .005 M Na₂S₂O₃-.
Discussion: 1.The sign of delta S would have to be positive. When considering the equation of the most important thing to realize is this isa(IO₃)₂(s) Ba²⁺(aq) 2IO₃(aq)B= + a reaction with a phase change. A solid substance would be more ordered and transitioning to an aqueous state makes the substance less ordered. This will increase the entropy and therefore delta S will be positive. 2.It is not necessary to preserve the original temperature. The solutions that had been resting in their specific temperature have already dissociated as much as they would at that temperature. At a higher temperature, the Ksp value is higher, so more solid was dissociated into aqueous solution. That aqueous solution is what was later used in a titration. The specific amount of solid has already started to form when the titration begins and the temperature decreases. The Thiosulfate in the titration will bond with the Iodate, which prevents the Barium and Iodate from forming more solid. The solid that has already formed will then continue to dissociate to reach equilibrium. Questions: Find the amount of in grams that dissolved in 4.00 mL of solution at 70℃:a(IO₃)₂(s)B