A what is the ph of this solution 5 pts b what is the

This preview shows page 3 - 5 out of 5 pages.

a) What is the pH of this solution? 5 ptsb) What is the % of benzoic acid ionized in this solution?5 pts
Information that may prove useful in this exam:Go= -RT ln KeqGorxn= Σcoeffproducts* Gof productsΣcoeffreactants* Gof reactantsln Keq= (- Ho/RT) + (So/R)R = 8.314 JK-1mol-1pX = - log XKW = 1.0 x 10-14Hof(kJ/mol)Gof(kJ/mol)So(Jmol-1K-1)Ca(s)0041.6Ca+2(aq)-543.0-553.6-56.2Mg(s)0032.67Mg+2(aq)-467.0-454.8-137Cl(g)121.3105.3165.2Cl2(g)00223.1Cl-(aq)-167.1-131.056.5MgCl2(s)-641.3-591.889.6CaCl2(s)-795.4-748.8108.4
Answers:1. Keq= [D]eqd[E]eqe/[B]eqb2. 5.12 x 10113.a) No changeb) Less MgCl2dissolvedc) No changed) More MgCl2dissolvede) More MgCl2dissolved4.a) 0.0037b) 2.69 x 10-12c) 11.57d) acidic5.H2SO4(sulfuric acid)HNO3(nitric acid)HClO4(perchloric acid)HCl (hydrochloric acid)HBr (hydrobromic acid)HI (hydroiodic acid)6. 5.7 x 10-47. (NO2)-18.“More than 7”Extra credit: pH = 8.479. pH = -0.17610.a) pH = 2.24b) 1.14 %

  • Left Quote Icon

    Student Picture

  • Left Quote Icon

    Student Picture

  • Left Quote Icon

    Student Picture