4. current qtr per share earning=0.2064 S=0.2654=sqrs(sum current – mean)^2/n-2)
Df=24 t0.025=2.064 CI=0.2064+-2.064*(0.2654/sqr25)=(0.1, 0.32) The earnings have increased. 5. Ho: u<=0 Ha: u>0 Differences is 177, -21, 186, -131, 22, 212, -5, 14 Mean=56.75 S=121.5445 t=56.75/121.5445/sqr8=1.32 df=7 p value >0.1 extract p value t-1.32 is 0.1142 p-value>0.1, don’t reject Ho. We conclude that airfares from Dayton are lower than those from Louisville at a=0.05 level of significance. 5. a. Ho: u=0 Ha: u not equal to 0 Mean=-18/15=-1.2 S=sqr54.4/14=1.97 T=-1.2/1.97/sqr15=-2.36 Df=14 Between 0.01 and 0.025 *2 P value between 0.02 and 0.05 Extract p-value t=-2.36 is 0.03333 P value <=0.05, reject Ho, we conclude that there’s a difference between the population mean weekly usage for the two media. 6. a. Ho: u=900 Ha: u is not equal to 900 b. xbar+-z0.025 sigma/sqrn=935+-1.96*180/sqr200=(910, 960) c.reject Ho since it is not in the interval. d. z=xbar-u/sigma/sqrn=935-900)/180/sqr200=2.75 p value=2×0.003=0.006 7.a Ho: u<=199155 Ha: u>199155 b. z=126000-119155/(20700/sqr60)=2.6 p value=1-0.9953=0.047 c. p value<=0.01, reject Ho. We conclude that the mean annual house hold income in san Francisco Bay area is higher that that for playbill readers. 8. Ho: u=2.357
Ha: u not equal to 2.357 Xbar=2.3496 S=-0.0444 T=2.3496/2.357/0.444/sqr50=-1.18 Df=49 P value between 0.1 and 0.2 *2 P value between 0.2 and 0.4 Extract p value t=-1.18 is 0.2437 P value >0.05, don’t reject Ho 9. a. Ho: p<=0.5 Ha: p>0.5 b. pbar=64/100=0.64 c. z=0.64/0.5/sqr0.5*.5/100=2.8 p value= 1-0.9974=0.0026 p value<=0.01 reject Ho. We conclude college graduates have a greater stop-smoking success rate.
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- Spring '08
- Statistics, Statistical hypothesis testing, Equals sign