11.
Looking up any values necessary, use the equation for universal gravitation to calculate the size of the following gravitational
forces:
a.
The force of the sun on Jupiter
b.
The force of the sun on an 80 kg human, who is standing on the surface of the Earth
c.
The force of the Earth on an 80 kg human, who is standing on the surface of the Earth
d.
The force of the same 80 kg human on the Earth
The gravitational force has a direction as well as a magnitude—it is a vector. Here is the expression for the force of the sun
on the planet Jupiter:
Handout 1
•
p . 4
Using GlowScript to Solve Problems
Lesson
6
(PHYSICS, PROGRAMMING)

Journeys in Film
: Hidden Figures
12.
The ^ or “hat” over the last r
SJ
means that it is a “unit vector.” A unit vector is a vector that has a magnitude of 1. Unit
vectors are useful in situations where direction is important, but magnitude is not. Identify which of the following are unit
vectors:
a.
b.
c.
d.
13.
A unit vector can be created by dividing a vector by its magnitude. When this process is carried out, the arrow over
the vector is replaced by the hat. For example,
. The symbol
is pronounced “vee hat.” Calculate the unit vector
versions of each of the following vectors:
a.
m
b.
kg•m/s
14.
What are the units of a unit vector?
15.
The vector
is the vector pointing from the sun to Jupiter. Make a sketch of the sun and Jupiter, and show the following
vectors:
,
,
, and
. Which way does
point? Why is there a negative sign in the equation?
16.
Create a new GlowScript program called “Sun-Jupiter,” copy this code into the program, and run it. Verify that you see a
yellow sphere representing the sun and a red sphere representing Jupiter.
GlowScript 2.4 VPython
scalefactor = 100
G = 6.67E-11
# universal
gravitational constant,
SI units
mS = 1.99E30
# mass of Sun, kg
mJ = 1.90E27
# mass of Jupiter, kg
RJ = 6.99E7
# radius of Jupiter, m
Handout 1
•
p . 5
Using GlowScript to Solve Problems
Lesson
6
(PHYSICS, PROGRAMMING)

Journeys in Film
: Hidden Figures
RS = 6.96E8
# radius of Sun, m
dSJ = 7.78E11
# mean distance of Jupiter from Sun, m
T = 11.86* 365.25*24*60*60
# orbital period of Jupiter
speed = 2*pi*dSJ/T
Sun = sphere(pos=vec(0,0,0), radius=RS*scalefactor, color=color.yellow)
Jupiter = sphere(pos=vec(dSJ,0,0), radius=RJ*scalefactor, color=color.red,
make_trail=True)
a.
Change the value of
scalefactor
to 50, and run the program again. Then change it to 10, and run the program.
What value of
scalefactor
displays a representation to scale of the sun and Jupiter? What does the program display
when you use this value?
b.
The orbital period of Jupiter is 11.86 years. This is the time is take Jupiter to orbit the sun once. Explain the other factors
in the calculation of
T
in the program.
c.
Describe the speed that the line
speed = 2*pi*dSJ/T
is calculating. Why does it work?
Add the following code to your Sun-Jupiter program.

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