Previous answers a major league baseball pitcher

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Principles of Geotechnical Engineering
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Chapter 15 / Exercise 15.16
Principles of Geotechnical Engineering
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9.6/6 points |Previous AnswersA major league baseball pitcher throws a pitch that follows these parametric equations:x(t) =140ty(t) = –16t2+5t + 5.The time units are seconds and the distance units are feet. The distance between the location of the pitcher and homeplate (where thebatter stands) is 60.5 feet. Give EXACT answers, unless instructed otherwise.(a) Calculate the horizontal velocity of the baseball at timet; this is the functionx'(t)=
(b) What is the horizontal velocity of the baseball when it passes over homeplate?
(c) What is the vertical velocity of the baseball at timet; this is the functiony'(t)=
(d) Recall that the speed of the baseball at timetiss(t)=√[x'(t)]2+ [y' (t)]2ft/sec.What is the speed of the baseball (inmph) when it passes over homeplate?
(e) At what time does the baseball hit the ground, assuming the batter and catcher miss the ball?
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Principles of Geotechnical Engineering
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Chapter 15 / Exercise 15.16
Principles of Geotechnical Engineering
Das/Sobhan
Expert Verified
sec.(f) What is themagnitudeof the angle at which the baseball hits the ground?
answer in radians to three decimal places.)
10.12/12 points |Previous AnswersConsider an object moving in the plane whose location at timetseconds is given by the parametric equations:x(t)=5cos(πt)y(t)=3sin(πt).Assume the distance units in the plane are meters.(a) The object is moving around an ellipse (as in the previous problem) with equation:x2a2+y2b2=1where a=$$5and b=$$3.(b) The location of the object at time t=1/3 seconds is($$52,$$3√32).(c) The horizontal velocity of the object at time t is x ' (t)=Viewing SavedWorkRevert toLast Response

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