# 4 parenleftbigg 1 5 1 5 parenrightbigg parenleftbigg

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4.0=parenleftbigg1.51.5parenrightbigg parenleftbigg3.02.0parenrightbiggy2.25 = 1.5yln 2.25 =yln 1.5y=ln 2.25ln 1.5= 2Msci 16 031600510.0 pointsThe following data were collected for the re-action2 A + B2+ CDInitialInitialInitialInitial[A][B2][C]rate(M)(M)(M)(M/s)10.010.010.011.250×10320.020.010.015.000×10330.030.010.051.125×10440.040.020.018.000×104Find the rate law.1.Rate = (1.25×1011) [A]2[B2]2correct2.Rate = (1.25×107) [A] [B2] [C]23.Rate = (1.25×107) [A]2[B2]24.Rate = (1.25×109) [A] [B2]25.Rate = (1.25×109) [A]2[B2]Explanation:
Version 001 – Extra Kinetics problems – shear – (49340)3Rate =k[A]x[B2]y[C]zFrom the information above for 3 experi-ments, determine the missing concentrationsof A and B. Answers should be in the order of[A] then [B].
Version 001 – Extra Kinetics problems – shear – (49340)4the following data were collected.time, s[A], M01.0010.43020.27030.20040.160What is the order of the reaction and therate constant?
Explanation:ChemPrin3e T13 1900810.0 pointsConsider the concentration-time dependencegraph for two first-order reactions.[A]0Molar Concentrationof ReactantConcentration-→