MATH
PP Section 6.3

# 120 60 2 3 180 2 3 2 π in which quadrant is the

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120 ) 60 ( 2 3 ) 180 ( 2 3 2 = = = π

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In which quadrant is the terminal side of this angle? Quadrant 2 What is the reference angle? Reference angle 3 2 π In Quadrant 2, the reference angle is π - θ or 180° – θ, if working with degrees. 60 3 3 2 angle ref = = - = π π π Draw the 30°-60° triangle to find point.
3 2 π 60 3 3 2 angle ref = = - = π π π 1 2 3 Since the point must be on the unit circle, the radius needs to be one. We then need to divide all the sides of the triangle by 2. ( 29 2 3 2 1 , - = P We also need to remember that in Quadrant 2, the x -coordinate is negative and the y -coordinate is positive.

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b a b a a b a b b a P 1 csc tan 1 sec cos cot sin then , of side terminal the and circle unit on the point the is ) , ( If : Recall = = = = = = = θ θ θ θ θ θ θ
3 2 csc 3 tan 2 sec cos 3 1 cot sin : Hence 3 2 3 2 3 2 2 1 3 2 3 2 2 3 3 2 = - = - = - = - = = π π π π π π ( 29 2 3 2 1 , - = P

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Example . 4 5 of functions tric trigonome the of value the Find π θ = What is the measure of this angle in degrees? 225 ) 45 ( 5 4 ) 180 ( 5 4 5 = = = π
In which quadrant is the terminal side of this angle? Quadrant 3 What is the reference angle? Reference angle 4 5 π 45 4 4 5 angle ref = = - = π π π Draw the 45°- 45° triangle to find point. In Quadrant 3, the reference angle is θ – π or θ - 180°, if working in degrees.

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4 5 π 45 4 4 5 angle ref = = - = π π π 1 1 2 Since the point must be on the unit circle, the radius needs to be one.
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