# The of original kno 3 mass will autofill from g65 and

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The % of original KNO 3 mass will autofill from G65 and G76. Plot a graph of solubility of KNO 3 (g KNO 3 / 100 g H 2 O) vs. Temperature( o C) and place it here. Cover this instruction box so that you graph is appropriately sized. Be sure to include a title, axis labels, and use the chart type that connects the data points. Note: You added a volume of water to the test tube. Assuming a density of 1.0g/mL, enter the g of water used in this part of the experiment. Use this when calculating the solubility in the table below. Note: Data is being restated here for ease in plotting. The cells for % impurity will autofill from cells G56, G122, and G155. Use the “slope” and “intercept” functions in Excel to get the slope and y-int. for calculating soln and soln . You did this in the report for Lab 2. By signing below, you certify that you have not falsified data, that you have not plagiarized any part of this lab report, and that all calculations and responses other than the reporting of raw data are your own independent work. Failure to sign this declaration will cost you 5 points. Signature: Type your calculation for molarity of Fe 2+ (1 mol ferroin = 1 mol Fe 2+ ) (0.104g)/(596.27g/mol)= 1.74e-4 mol Ferroin = 1.74e-4 mol Fe2+ (1.74e-4 mol Fe2+)/(0.01 L)= 1.74e-2 M Fe2+ Type your calculation for moles of Fe 2+ ERROR:please see #4 in evaluation we forgot the step of saving a KNO3 portion therefore, we are unable to obtain an accurate numerica value for the moles of Fe+ in the solution. Hypothetically speaking, we were supposed to save about 0.1 grams, so the calculation for saving 0.1 g is: 0.1g/(55.845 g/mol)= 1.79e-3 mol Fe2+ Type your calculation for grams of (NH 4 ) 2 Fe(SO 4 ) 2 .6H 2 O 1.79e-3mol Fe2+ = 1.79e-3mol (NH4)2Fe(SO4)2.6H2O) (1.79e-3mol (NH4)2Fe(SO4)2.6H2O))*(391.975 g/mol (NH4)2Fe(SO4)2.6H2O)) = 0.702 g (NH4)2Fe(SO4)2.6H2O) Type your calculation for % mass of (NH 4 ) 2 Fe(SO 4 ) 2 .6H 2 O in the crystals. 0.398g crystals + 0.1g crystals = 0.498 g crystals 0.1g/0.498g= 0.2008 x 100%= 20.08% (NH4)2Fe(SO4)2.6H2O) crystals 55.845g Fe2+/(391.975g (NH4)2Fe(SO4)2.6H2O))= 0.142*0.2008= 0.0285*100%= 2.85% Laboratory Waste Evaluation (1 pt) Laboratory waste is considered anything generated during an experiment that is disposed of down the sewer drain, thrown in the garbage, collected in a container for disposal by the UW Environmental Health & Safety department, or released into the environment. Based on the written lab procedure and your actions during the lab, list the identity and approximate amount (mass or volume) of waste that you generated while performing this experiment. ice for ice bath 100 ml water 0.5 g (NH4)2Fe(SO4)2.6H2O 4.5 g KNO3 few filter papers a few drops of water 7ml of water 2 ml hydroxylamine solution 5 ml phenanthroline solution 150 ml water 7 g KNO3 Note: All sections of this report must be typed. 0
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