x 01 mol 0001 moles Ca 2 1 1000 mL 1 L Mole EDTA 1270 mL EDTA x 1 Liter x 01

X 01 mol 0001 moles ca 2 1 1000 ml 1 l mole edta 1270

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x .01 mol=.0001 moles Ca2+1 1000 mL 1 LMole EDTA:12.70 mL EDTAx 1 Liter x .01 moles = 1.27x10-4moles EDTA1 1000 mL 1 LiterIII. A.Sample Calculations for Trial 1:Ca2+:10 mLx 1 Lx .01 mol=.0001 moles Ca2+1 1000 mL 1 LMole EDTA:12.70 mL EDTAx 1 Liter x .01 moles = 1.27x10-4moles EDTA1 1000 mL 1 LiterB. From the data it appears that EDTA reacts with Ca2+with a 1:1 mole ratio. Given that information, this equation seems logical: Ca2+(aq) + EDTA4-(aq) → CaEDTA2-(aq)IV. A.In this section, the same procedure was executed without precise measurement. EDTA4-(aq) was combined with the other cations to yield the following:CationFe3+K+Na+Mg2+SuccessNoNo No Yes
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The cations iron(III), potassium, and sodium would not have worked because the color the exhibited before titration was the same color that they would have exhibited after titration.B. Cations with a 2+ charge can be determined by being titrated with EDTA. Out of the 3 cations that were shown to make hard water in part I, 2 of these cations had a 2+ charge.C. Assumption 1: Ca2+(aq) + EDTA4-(aq) → CaEDTA2-(aq)Equation can also be used to assume CaCO3ratio with EDTA is 1:1.Calculation: 12.35 mL EDTA x 1 Literx .0114 moles= 1.4079x10-4 moles EDTA1 1000 mL 1 LVolume: 30 mL H2O + 12.35 mL EDTA = 42.35 mL = .04235 L1.4079x10-4moles CaCO3x 100.09 grams x 1000 mgx __1__= 332.7 mg/L CaCO31 mol CaCO31 gram .04235 LV. Alkalinity DataNa2CO3CaCl2Na3PO4Na2SO4Dist. H2OConcentration.0017 M.0017 M.0017 M.0017 M-Volume50 mL50 mL50 mL50 mL50 mLNa2CO3CaCl2Na3PO4Na2SO4Dist. H2OBuiret pHReading Buiret pHReading Buiret pHReading
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  • Spring '16
  • Christine Gaudinski
  • Chemistry, ml

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