x 01 mol 0001 moles Ca 2 1 1000 mL 1 L Mole EDTA 1270 mL EDTA x 1 Liter x 01

# X 01 mol 0001 moles ca 2 1 1000 ml 1 l mole edta 1270

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x .01 mol=.0001 moles Ca2+1 1000 mL 1 LMole EDTA:12.70 mL EDTAx 1 Liter x .01 moles = 1.27x10-4moles EDTA1 1000 mL 1 LiterIII. A.Sample Calculations for Trial 1:Ca2+:10 mLx 1 Lx .01 mol=.0001 moles Ca2+1 1000 mL 1 LMole EDTA:12.70 mL EDTAx 1 Liter x .01 moles = 1.27x10-4moles EDTA1 1000 mL 1 LiterB. From the data it appears that EDTA reacts with Ca2+with a 1:1 mole ratio. Given that information, this equation seems logical: Ca2+(aq) + EDTA4-(aq) → CaEDTA2-(aq)IV. A.In this section, the same procedure was executed without precise measurement. EDTA4-(aq) was combined with the other cations to yield the following:CationFe3+K+Na+Mg2+SuccessNoNo No Yes
The cations iron(III), potassium, and sodium would not have worked because the color the exhibited before titration was the same color that they would have exhibited after titration.B. Cations with a 2+ charge can be determined by being titrated with EDTA. Out of the 3 cations that were shown to make hard water in part I, 2 of these cations had a 2+ charge.C. Assumption 1: Ca2+(aq) + EDTA4-(aq) → CaEDTA2-(aq)Equation can also be used to assume CaCO3ratio with EDTA is 1:1.Calculation: 12.35 mL EDTA x 1 Literx .0114 moles= 1.4079x10-4 moles EDTA1 1000 mL 1 LVolume: 30 mL H2O + 12.35 mL EDTA = 42.35 mL = .04235 L1.4079x10-4moles CaCO3x 100.09 grams x 1000 mgx __1__= 332.7 mg/L CaCO31 mol CaCO31 gram .04235 LV. Alkalinity DataNa2CO3CaCl2Na3PO4Na2SO4Dist. H2OConcentration.0017 M.0017 M.0017 M.0017 M-Volume50 mL50 mL50 mL50 mL50 mLNa2CO3CaCl2Na3PO4Na2SO4Dist. H2OBuiret pHReading Buiret pHReading Buiret pHReading

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• Spring '16
• Christine Gaudinski

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