Harder you push on electricelectrical current rt rate

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
•Harder you push on electric=↑electrical current •R(t)( rate of decay )=R 0 e -λt =λN(t) (R 0 =activity) •There isn’t a physical move inelectrons, but there was a voltage pulse •λ(Decays/Second)=0.693/T ½ which causes you to react to a situation Flow of current=transverse •T e ff =T p T b /T p +T b (p=physical, b=biological) •Electrical charge, in and out the cell, membrane changes voltage •Ratio: 2e -t(λ- λ) (2:depending on how many more ions there are, λ=.693/ T ½ ) which propagates down the cell •Since the mass of the nucleus is proportional to A, the density of the nuclear material is independent of A •What defines the voltage across the cell membrane? •Stability is a competition b/t the repulsive Coulomb force between protons and the attractive “strong” The charge outside & inside the membrane Interaction between nucleons. (Unlike the Coulomb force, nuclear force has a very short range) •Higher concentration= ↑ diffusion=more voltage to turn diffusion off •Positive charges repel each other, why is it stable? Repulsive force between 2 protons there should be •Voltage difference due to concentration Attractive forces and coulomb forces •Diffusion:High to Low •Extra neutrons aid stability but too few or too many may cause in stability •Nernst Potential:
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern