O o o o o o o o most deshielded proton most shielded

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O O O O O O O O Most deshielded proton Most shielded carbon 12. (4) The 1 H-NMR spectrum of TNT has a singlet at 9.0 ppm, a much higher chemical shift than normal for benzene ring protons. Using ten words or less in each case write two different reasons or phenomena that account for this unusually high chemical shift. Reason #1 ( ten words or less ) : Reason #2 ( ten words or less ) : 13. (6) Explain the origin of splitting in a 1 H-NMR spectrum. Use no more than 40 words . Your explanation may include a picture, but a picture is not required. 14. (4) Complete each sentence by writing no more than three words in each blank. (a) X-ray crystallography depends on diffraction of x-ray photons by an atom’s __________________. (b) Constructive and destructive interference of scattered x-ray photons produces the ______________. This reveals the position of atoms in space within the ___________________. (c) Liquids and gases cannot be studied using x-ray crystallography because these substances are not __________________.
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Chemistry 14C Lecture 1 Spring 2010 Exam 2 Page 4 Page 4 score = 15. (9) Draw in the box a molecule that is consistent with the given molecular formula, IR, and NMR data. Use the back of the spectroscopy data page, or back of the previous exam page, for scratch paper if needed . No partial credit for these problems. (a) Formula : C 4 H 8 O 2 IR : OH (3408 cm -1 ) and C=O (1709 cm -1 ). 1 H-NMR : 3.8 ppm (triplet; integral = 2), 3.4 ppm (singlet; integral = 1), 2.7 ppm (triplet; integral = 2), and 2.2 ppm (singlet; integral = 3). 13 C-NMR : 209 ppm (singlet), 58 ppm (triplet), 46 ppm (triplet), and 30 ppm (quartet). (b) Formula : C 4 H 8 O 2 IR : OH (2950 cm -1 ) and C=O (1712 cm -1 ). 1 H-NMR : 11.5 ppm (singlet; integral = 1), 2.3 ppm (triplet; integral = 2), 1.7 ppm (sextet; integral = 2), and 1.0 ppm (triplet; integral = 3). 13 C-NMR : 181 ppm (singlet), 36 ppm (triplet), 18 ppm (triplet), and 14 ppm (quartet).
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