The carts acceleration will double as the numerator

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What is the expression for the acceleration now? (Use the following as necessary: m1, m2, and g.)f,
2)Based on your answers to the previous parts, what conclusion can you draw about theacceleration of the cart?Additional MaterialsNewton's Second LawAppendix
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4.10/10 points | Previous AnswersIn the diagram below, indicates the pulling force and the friction force acting on the object. Thedirection of motion of the object is indicated by the velocity vector .Figure AFigure BFigure CFor each case, indicate the direction of the net force, the direction of the acceleration of the object andstate whether the object is speeding up, slowing down, or moving with constant velocity. The forcevectors are drawn to scale.Direction of net forceDirection of accelerationThe object isAto the left to the leftto the left to the leftslowing down slowing downBto the right to the rightto the right to the rightspeeding up speeding upCThe net force is zero. The net force is zero.The acceleration is zero. The acceleration is zero.moving with constant velocity moving with constant velocityAdditional MaterialsNewton's Second LawAppendix5.34.3/35 points | Previous AnswersA simple Atwood machine consists of two masses m1and m2that are connected by a string wound overa pulley, as seen in the figure below. Assume m2is larger than m1. Motion in the upward direction ispositive. On a piece of paper, draw two free body diagrams; one for each of the masses, showing allforces acting on each mass. Then answer the following questions.

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