b lim n 2 1 n lim n 2 1 n 2 n 2 1 n lim 1 n 2 1 n lim 1 n q 1 1 n 2 1 lim 1 n

B lim n 2 1 n lim n 2 1 n 2 n 2 1 n lim 1 n 2 1 n lim

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(b)lim(n2+ 1-n) = lim(n2+ 1)-n2n2+ 1 +n= lim1n2+ 1 +n= lim1nq1 +1n2+ 1=lim1nlimq1 +1n2+ 1=01= 0.68
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(c)lim(n2+n-n) = lim(n2+ 1)-n2n2+n+n= limnn2+n+n= lim1q1 +1n+ 1=1limq1 +1n+ 1=11 + 1=12.69
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  • Fall '08
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  • Limits, lim, Limit of a function, Limit of a sequence, Suppose sn

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