LAB 1 Molecular Weight Determined by Vapor Method pdf.pdf

120036 g 119467 g 0569 g unknown number 728040 trial

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120.036 g — 119.467 g = 0.569 g Unknown number 728040 Trial 1 Trial 2 Mass of flask + cap + band 122.735 g 119.467 g Temperature of boiling H 2 O (°C) 96.5 °C 96.5 °C Temperature of boiling H 2 O (K) 369.65 K 369.65 K Mass of flask + cap + band + condensed liquid 123.284 g 120.036 g Mass of condensed liquid 0.549 g 0.569 g Volume of 250 mL flask 1) 89.9 mL + 94.9 mL + 93.1 mL = 277.9 mL 2) 93.4 mL + 95.9 mL + 97.9 mL + 29.1 mL = 316.3 mL Atmospheric pressure 679.0 mm Hg 0.893 atm Molecular weight (MW) of unknown 67.1 g/mole 61.1 g/mole Average molecular weight 64.1 g/mole
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Emma Quinn Chem 1120-102 Tuberty 3. The calculations to obtain the pressure, volume, and temperature values you used in the ideal gas law (equation 1) for trial 2. P = = 0.893 atm V = 93.4 mL + 95.9 mL + 97.9 mL + 29.1 mL = 316.3 mL V = = 0.3163 L T = 96.5 °C + 273.15 K = 369.65 K 4. The calculation to determine moles of substance present for trial 2 using the ideal gas law equation. 5. The calculation for the molecular weight (MW) of your unknown for trial 2. 6. The calculation for the average molecular weight of your unknown. 67.1 g/mol + 61.1 g/mol = 128.2 g/mol ÷ 2 = 64.1 g/mol 7. Answer the following questions. Show all work! 1. Give the correct chemical formulas for the following: a) lithium hydride- LiH b) hydrobromic acid- HBr c)
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