Enter the domain in interval notation to enter type

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Enter the domain in interval notation. To enter , type infinity. Your response Correct response (-2,infinity) (-2, infinity) Auto graded Grade: 1/1.0 The vertical asymptote is Your response Correct response -2 -2 Auto graded Grade: 1/1.0 As approaches the vertical asymptote, Your response Correct response -infinity -infinity Auto graded Grade: 1/1.0 . As approaches , Your response Correct response infinity infinity Auto graded Grade: 1/1.0 . Which of the following graphs best represents the graph of ? Your response Correct response b = e y = - 4.8 x = h = h e - 4.8 ln( h ) = - 4.8 g ( x ) = ln(5 x + 10) + 1.4 ! x = ! x g ( x ) ! x g ( x ) ! g ( x )
9/29/20, 5 : 08 PM Southern New Hampshire University - Page 15 of 23 Auto graded Grade: 1/1.0 Show your work and explain, in your own words, how you arrived at your answers. Answers with no relevant explanations may receive reduced or no credit. ! as x 2, g ( x ) → -∞ and as x + , g ( x ) → ∞
9/29/20, 5 : 08 PM Southern New Hampshire University - Page 16 of 23 The input must be positive. Subtract . Divide by . The domain of is and the vertical asymptote is . The graph of is shown in the figure below. As , and as , . Question9: Score 0/0 Find the exact solution for If there is no solution, enter NA.Enclose arguments of functions in parentheses and include a multiplication sign between terms. Forexample, * log(h) . . 5 x + 10 > 0 5 x > - 10 10 x > - 2 5 g ( x ) = ln(5 x + 10) + 1.4 ( - 2, ) x = - 2 g ( x ) = ln(5 x + 10) + 1.4 x 2 g ( x ) → -∞ x + g ( x ) → ∞ - 5 - 50 = 0 e 2 x e x c
9/29/20, 5 : 08 PM Southern New Hampshire University - Page 17 of 23 Your response Correct response ln(10) ln(10) Auto graded Grade: 1/1.0 Show your work and explain, in your own words, how you arrived at your answer. Answers with no relevant explanations may receive reduced or no credit. factor the equation (e^x-10)(e^x+5)=0 If any factor on the left side of the equation is equal to 0 the entire expression is now 0 so e^x-10 is equal to 0 and we solve for x x=ln(10) The final solution is all the values that make (ex 10)(ex+5)=0 true. x=ln(10) Ungraded Grade: 0/1.0 Total grade: 1.0 × 1/2 + 0.0 × 1/2 = 50% + 0% Feedback: Factor by the FOIL method. or If a product is zero, then one factor must be zero. or Isolate the exponentials. Reject the negative equation. Solve the positive equation. Question10: Score 0/0 Use the one-to-one property of logarithms to find an exact solution for x = ! " - 5 - 50 e 2 x e x = 0 ( - 10)( + 5) e x e x = 0 - 10 e x = 0 + 5 e x = 0 e x = 10 e x = - 5 e x = 10 x = ln(10)
9/29/20, 5 : 08 PM Southern New Hampshire University - Page 18 of 23 . If there is no solution, enter NA. The field below accepts a list of numbers or formulas separated by semicolons (e.g.

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