Enter the domain in interval notation. To enter
, type infinity.
Your response
Correct response
(2,infinity)
(2, infinity)
Auto graded
Grade:
1/1.0
The vertical asymptote is
Your response
Correct response
2
2
Auto graded
Grade:
1/1.0
As
approaches the vertical asymptote,
Your response
Correct response
infinity
infinity
Auto graded
Grade:
1/1.0
.
As
approaches
,
Your response
Correct response
infinity
infinity
Auto graded
Grade:
1/1.0
.
Which of the following graphs best represents the graph of
?
Your response
Correct response
b
=
e
y
=

4.8
x
=
h
=
h
e

4.8
ln(
h
) =

4.8
g
(
x
) = ln(5
x
+ 10) + 1.4
∞
!
x
=
!
x
g
(
x
)
→
!
x
∞
g
(
x
)
→
!
g
(
x
)
9/29/20, 5
:
08 PM
Southern New Hampshire University 
Page 15 of 23
Auto graded
Grade:
1/1.0
Show your work and explain, in your own words, how you arrived at your answers.
Answers
with no relevant explanations may receive reduced or no credit.
!
as x
→
2,
g
(
x
)
→ ∞
and as x
→
+
∞
,
g
(
x
)
→ ∞
9/29/20, 5
:
08 PM
Southern New Hampshire University 
Page 16 of 23
The input must be positive.
Subtract
.
Divide by .
The domain of
is
and the vertical asymptote is
.
The graph of
is shown in the figure below.
As
,
and as
,
.
Question9:
Score 0/0
Find the exact solution for
If there is no solution, enter NA.Enclose arguments of functions in parentheses and include a multiplication sign between terms. Forexample, * log(h)
.
.
5
x
+ 10 > 0
5
x
>

10
10
x
>

2
5
g
(
x
) = ln(5
x
+ 10) + 1.4
(

2,
∞
)
x
=

2
g
(
x
) = ln(5
x
+ 10) + 1.4
x
→
2
g
(
x
)
→ ∞
x
→
+
∞
g
(
x
)
→ ∞

5

50 = 0
e
2
x
e
x
c
9/29/20, 5
:
08 PM
Southern New Hampshire University 
Page 17 of 23
Your response
Correct response
ln(10)
ln(10)
Auto graded
Grade:
1/1.0
Show your work and explain, in your own words, how you arrived at your answer.
Answers
with no relevant explanations may receive reduced or no credit.
factor the equation
(e^x10)(e^x+5)=0
If any factor on the left side of the equation is equal to 0 the entire expression is now 0
so e^x10 is equal to 0 and we solve for x
x=ln(10)
The final solution is all the values that make (ex
−
10)(ex+5)=0 true.
x=ln(10)
Ungraded Grade:
0/1.0
Total grade: 1.0
×
1/2 + 0.0
×
1/2 = 50% + 0%
Feedback:
Factor by the FOIL method.
or
If a product is zero, then one factor must be zero.
or
Isolate the exponentials.
Reject the negative equation.
Solve the positive equation.
Question10:
Score 0/0
Use the onetoone property of logarithms to find an exact solution for
x
=
!
"

5

50
e
2
x
e
x
= 0
(

10)(
+ 5)
e
x
e
x
= 0

10
e
x
= 0
+ 5
e
x
= 0
e
x
= 10
e
x
=

5
e
x
= 10
x
= ln(10)
9/29/20, 5
:
08 PM
Southern New Hampshire University 
Page 18 of 23
.
If there is no solution, enter NA.
The field below accepts a list of numbers or formulas separated by semicolons (e.g.