# Select one a 6 m b 194 m c 237 m d 4 m feedback the

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Select one: a. 6 m b. 194 m c. 237 m d. 4 m Feedback The correct answer is: 194 m Question 10 Incorrect 0.00 points out of 6.25
Flag question Question text Identify the vertex and determine the minimum or maximum value of the function. f ( x ) = -2 x 2 + 8 x - 2 Select one: a. Vertex: (2, -6) Maximum: -6 b. Vertex: (2, 6) Maximum: 6 c. Vertex: (2, -6) Minimum: -6 d. Vertex: (2, 6) Minimum: 6 Feedback The correct answer is: Vertex: (2, 6) Maximum: 6 Question 11 Incorrect 0.00 points out of 6.25 Flag question Question text
Determine if the graph can represent a polynomial function. If so, assume the end behavior and all turning points are represented on the graph. a . Determine the minimum degree of the polynomial based on the number of turning points. b. Determine whether the leading coefficient is positive or negative based on the end behavior and whether the degree of the polynomial is odd or even. c. Approximate the real zeros of the function, and determine if their multiplicity is odd or even. Select one: a. a. Minimum degree 2 b. Leading coefficient positive degree even c. -1.6 and -4.4 (each of odd multiplicity) b. Not a polynomial function. c. a. Minimum degree 2 b. Leading coefficient positive degree even c. -2 (even multiplicity)
d. a. Minimum degree 3 b. Leading coefficient negative degree odd c. -2 (even multiplicity) Feedback The correct answer is: Not a polynomial function. Question 12 Correct 6.25 points out of 6.25 Flag question Question text Sketch the function. f ( x ) = - x 4 + 15 x 2 - 44 Select one: a.
b. c.
d. Feedback The correct answer is: Question 13 Correct 6.25 points out of 6.25 Flag question
Question text Use long division to divide. ( x 5 + 2 x 4 - 2 x 2 - 5 x - 12) ÷ ( x 2 - 3) Select one: a. x 3 + 2 x 2 + 7 x + 4 b. x 3 + 2 x 2 - 3 x - 8 + c. x 3 + 2 x 2 + 3 x + 4 + d. x 3 + 5 x 2 + 13 + Feedback The correct answer is: x 3 + 2 x 2 + 3 x + 4 + Question 14 Incorrect 0.00 points out of 6.25 Flag question Question text Solve the problem.