Part f a box of mass texttipmm is sliding down a

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Algebra and Trigonometry
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Chapter 1 / Exercise 109
Algebra and Trigonometry
Redlin/Stewart
Expert Verified
done on the dresser.A box of mass\texttip{m}{m}is sliding down a frictionless plane that is inclined at an angle\texttip{\phi }{phi}abovethe horizontal, as shown in the figure . What is the workdone on the box by the force due to gravity\texttip{w}{w},if the box moves a distance\texttip{d}{d}?W\;>\;1.75\times 10^4\;\rm{J}W\;=\;1.75\times 10^4\;\rm{J}1.75\times 10^4\;\rm{J}\;>\; W\; >\;0\;\rm{J}W\;=\;0\;\rm{J}
Part F
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Algebra and Trigonometry
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Chapter 1 / Exercise 109
Algebra and Trigonometry
Redlin/Stewart
Expert Verified
11/10/2014HW week 6Hint 1.Finding Theta.The work done on the box by the force of gravity depends on the angle between the weight and thedisplacement; this is the angle\texttip{\theta }{theta}that goes into the equationW = Fd\cos\theta.ANSWER:CorrectThe angle given to you in a problem is not always the same angle that you use in the equation for work!Finding the angleThe work done on the Earth by the gravitational attraction between it and the Sun depends on the anglebetween the gravitational force and the displacement of the Earth; this is the angle\texttip{\theta }{theta}thatgoes intoW = Fd\cos\theta.The force of attraction always points from the Earth toward the Sun along the radius of the Earth's orbit. Atany instant in time the displacement of the Earth is considered to be tangent to its orbit; perpendicular to theW = wd\cos\phiW = wd\cos(90 ­ \phi)W = 0None of thesePart GThe planet Earth travels in a circular orbit at constant speed around the Sun. What is the net work done on the Earthby the gravitational attraction between it and the Sun in one complete orbit? Assume that the mass of the Earth isHint 3.Finding the angleThe work done on the Earth by the gravitational attraction between it and the Sun depends on the anglebetween the gravitational force and the displacement of the Earth; this is the angle\texttip{\theta }{theta}thatgoes intoW = Fd\cos\theta.The force of attraction always points from the Earth toward the Sun along the radius of the Earth's orbit. Atany instant in time the displacement of the Earth is considered to be tangent to its orbit; perpendicular to theW = wd\cos\phiW = wd\cos(90 ­ \phi)W = 0None of these
11/10/2014HW week 629/61

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