Looking for given relationship solution momentum m200

This preview shows page 5 - 6 out of 6 pages.

Looking For Given Relationship Solution Momentum m=200 kg v=15 m/s P=mv = 200 x 15 P = 3000 kg m/s 22. Calculate the mass of a car traveling at 10 m/s that has a momentum of 4,000 kg m/s. Looking For Given Relationship Solution 5 | P a g e
Image of page 5

Subscribe to view the full document.

Mass p=4000 kg m/s v=10 m/s m=p/v = 4000/10 400 kg 23. What are the units of momentum? Impulse? Momentum = Kg m/s Impulse N·s 24. What is the formula for impulse? J = F*t 25. What is the difference between an elastic and an inelastic collision? Elastic collisions are where two objects collide and bounce off each other. Inelastic collisions are where two objects stick together after the collision. 26. Explain the physics behind padded dashboards. Padded dashboards increases contact time thus decrease force. 27. A 500-kg car moves at 5 m/s in 2 seconds. Determine the momentum of the car? Looking For Given Relationship Solution Momentum m=500 kg v=5 m/s P=mv 2500 kg m/s Calculate the impulse necessary to stop the car. Looking For Given Relationship Solution Impulse m=500 kg v=5 m/s Mv=Ft 2500 kg m/s Calculate the force acting upon the car as it comes to a stop. Looking For Given Relationship Solution Force m=500 kg v=5 m/s t=2 s Mv = Ft 1250 N 6 | P a g e
Image of page 6

{[ snackBarMessage ]}

Get FREE access by uploading your study materials

Upload your study materials now and get free access to over 25 million documents.

Upload now for FREE access Or pay now for instant access
Christopher Reinemann
"Before using Course Hero my grade was at 78%. By the end of the semester my grade was at 90%. I could not have done it without all the class material I found."
— Christopher R., University of Rhode Island '15, Course Hero Intern

Ask a question for free

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern