b Solve using the procedures that produce equivalent equations 4 x 3 x 9

# B solve using the procedures that produce equivalent

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b. Solve using the procedures that produce equivalent equations. – 9
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. cont’d SOLUTION
Classify each equation as a contradiction, a conditional equation, or an identity. 5
ABSOLUTE VALUE EQUATIONS
DEFINITION The absolute value of a number a is given by ABSOLUTE VALUE EQUATIONS . line number real the on a and x between ce tan dis the is a x , generally More . origin the to a of ce tan dis the represents it that and 0 a if a 0 a if a a
ABSOLUTE VALUE EQUATIONS
The following property is used to solve absolute value equations. A Property of Absolute Value Equations For any variable expression E and any nonnegative real number k , | E | = k if and only if E = k or E = – k ABSOLUTE VALUE EQUATIONS
EXAMPLE If | x | = 5, then x = 5 or x = –5. If | x | = , then x = or x = – . If | x | = 0, then x = 0. ABSOLUTE VALUE EQUATIONS
SOLVE AN ABSOLUTE VALUE EQUATION Solve: | 2 x – 5 | = 21 Solution: | 2 x – 5 | = 21 implies 2 x – 5 = 21 or 2 x – 5 = –21. Solving each of these linear equations produces 2 x – 5 = 21 or 2 x – 5 = –21 2 x = 26 2 x = –16 x = 13 x = –8
SOLVE EACH EQUATIONS 14 5 7 3 . 2 3 5 2 . 1 x x 2 3 1 - x . 4 15 6 5 3 . 3 x x
FORMULAS
Table 1.2 Formulas from Geometry FORMULAS
It is often necessary to solve a formula for a specified variable. Begin the process by isolating all terms that contain the specified variable on one side of the equation and all terms that do not contain the specified variable on the other side. FORMULAS
a . Solve 2 l + 2 w = P for l . b. Solve S = 2( wh + lw + hl ) for h . Solution: P w SOLVE A FORMULA FOR A SPECIFIED VARIABLE EXAMPLE
b . S = 2( wh + lw + hl ) S = 2 wh + 2 lw + 2 hl S – 2 lw = 2 wh + 2 hl S – 2 lw = 2 h ( w + l) cont’d

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• Spring '12
• edgar
• Math, Equations, Elementary algebra, ESTRADA, Division Property of Equality