89.
three times
5.
First, determine the unknowns.
Let x
the larger number and y
the smaller number.
=
=
The question asks us to find the value of the larger number and the value of the smaller number.
These are the unknown
values, so we set up the variables to represent these values.
Next, since there are two variables, write a system of equations in the two unknowns.
Start with the statement, "The sum of two numbers is
We write this in terms of the variables as
89."
x + y = 89.
Now, look at the statement, "If
the smaller number is subtracted from the larger number, the result is
We write
the smaller number" in terms of a variable as
three times
5."
"three times
3y.
The second equation of the system is written below.
x − 3y = 5
We now have the following system of equations in two unknowns.
x + y = 89
x − 3y = 5
Now, solve the system.
We can eliminate the x terms from the system by multiplying the second equation by
and then
adding it to the first equation.
− 1
Multiply the second equation by
.
− 1
( − 1)(x − 3y)
=
(5)( − 1)
− x + 3y =
− 5
We now have the following equivalent system of equations, which can be added together to eliminate the x terms.
x +
y
=
89
− x + 3y
=
− 5
y
4
=
84
Divide by
to solve for y.
4
y
4
=
84
y
=
21
Now find the value of x.
Substitute the value found for y into the first equation from the original system of equations.
x + y
=
89
x + 21
=
89
x
=
68
Therefore, the larger number is
and the smaller number is
.
These values can be substituted into the second equation in
the original system as a check.
68
21
Practice for the Final Exam: Chapter 4 Review-Barone Morales
1 of 1
4/1/2016 2:31 AM

Student:
Barone Morales
Date:
4/1/16
Instructor:
Carl Letsche
Course:
MATH110 D012 Win 16
Assignment:
Practice for the Final
Exam: Chapter 4 Review
Practice for the Final Exam: Chapter 4 Review-Barone Morales
1 of 2
4/1/2016 2:31 AM

Jen Butler has been pricing Speed-Pass train fares for a group trip to Washington D.C.
Three adults and four children must
pay $
.
Two adults and three children must pay
$
.
Find the price of the adult's ticket and the price of a child's ticket.
159
113
Read and reread the problem.
Let
A
the price of an adult's ticket
=
C
the price of a child's ticket
=
We translate the problem into two equations using both variables.
In words:
Three Adults
and
four children
must pay
159
Translate:
3A
+
4C
=
159
In words:
Two adults
and
three children
must pay
113
Translate:
2A
+
3C
=
113
Now solve the system.
3A + 4C = 159
2A + 3C = 113
Since both equations are in standard from, we solve by the addition method.
First we multiply the first equation by 2 and the
second equation by
3 so that when we add the equations we eliminate the variable A.
−
After the multiplication, the system is as follows
2(
)
simplifies to
3A + 4C = 159
6A + 8C = 318
3(
) simplifies to
−
2A + 3C = 113
− 6A − 9C = − 339
Next, add the two equations.

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