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Question 41 / 1 ptsGiven the following ANOVA table for three treatments each with six observations:What is the critical value of F at the 5% level of significance?3.293.683.593.20There are three treatments and a total of 18 observations, so k = 3 and n = 18. The treatment degrees of freedom are k - 1 = 3 - 1 = 2, and the error degrees of freedom are n - k = 18 - 3 = 15. Therefore, the F-distribution would have 2 degrees of freedom in the numerator and 15 degrees of freedom in the denominator. Using the "Critical values of the F distribution at a 5 percent level ofsignificance" table, the F critical value is 3.68.Question 51 / 1 pts
When testing for differences between treatment means, a confidence interval is computed with __________________.Question 61 / 1 ptsThe annual dividend rates for a random sample of 16 companies in three different industries, utilities, banking, and insurance were recorded. The ANOVA comparing the mean annual dividend rate among three industries rejected the null hypothesis that the dividend rates were equal. The Mean Square Error (MSE) was 3.36. The following table summarized the results:When comparing the mean annual dividend rate for companies in the utilities andinsurance industries, the following 95% confidence interval can be constructed: _________________.
Question 71 / 1 ptsTwo accounting professors decided to compare the variance of their grading procedures. To accomplish this, they each graded the same 10 exams, with the following results:The calculated F ratio is ______.3.4841.867