# 2 2 2 2 1 σ σ π σ x x x e g 5 5 2 1 x x 2 2 1 σ

This preview shows pages 11–15. Sign up to view the full content.

2 2 2 ) ( , 2 1 σ σ π σ X x X e G = " 5 ' 5 2 1 = = x X " 2 2 1 = σ (a) higher than 5’10” means Δ x = 4 ½ ” above the mean height, 8 . 1 " 2 / " 4 / 2 1 2 1 = = Δ = σ x t

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
t = 1.8. The value found in the table is 92.81. What percentage of the women are taller than 5’10” ? 92.81 3.6 The answer is (100 – 92.81)/2 3.6. 3.6% out of 2000 amounts to 72
The cutoff at 5’10” gives a t-value of 1.8 and 3.6% of women eligible to join. Now we want to have 7.2% of women being eligible. What do we do? 072 . 0 2 1 2 2 2 ) ( , = = h X x h X e G σ σ π σ We want to have 856 . 0 ) 072 . 0 2 100 ( , = = + σ σ σ t X t X X G

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
All the club has to do is lowering the bar by 1”, from 5’10” to 5’9”! 85.6 7.2 t -? 856 . 0 ) 072 . 0 2 100 ( ) ( , = = + x G t X t X X σ σ σ " 9 ' 5 " 2 46 . 1 " 5 ' 5 46 . 1 2 1 2 1 + = + = = σ t x h t
Typical situation - a sample (set) of N numeric values of the same parameter What are the things we usually want to know? Statistical analysis of data N x N x x x x i N = + + + = ... 2 1 = = N i i x x x N 1 2 2 ) ( 1 σ N x x x x x x ,..., , , , 4 3 2 1 = 1) The mean value: 2) The variance and standard deviation = = N i i x x x N 1 2 ) ( 1 σ
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern