Answer Key 178 Feedback Z Critical Value NORMSINV975 196 n n Question 6 of 20

# Answer key 178 feedback z critical value normsinv975

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Question 6 of 20Select the correct answer for the blank: If everything else stays the same, the requiredsample size ____ as the confidence level increases to reach the same margin of error. Answer:A. IncreasesB. DecreasesC. Remains the same
Question 7 of 20The FDA regulates that fresh Albacore tuna fish that is consumed is allowed to contain0.82 ppm of mercury or less. A laboratory is estimating the amount of mercury in tuna fish for a new
Page 3 of 12APUS CLE : MATH302 B005 Win 20 : Tests & Quizzes2/9/2020...
1.0/ 1.0 Pointscompany and needs to have a margin of error within 0.03 ppm of mercury with 95% confidence.Assume the population standard deviation is 0.138 ppm of mercury. What sample size is needed?Round up to the nearest integer. Answer: 82Answer Key:82Feedback:Z-Critical Value = NORM.S.INV(.975) = 1.96n = n = Part 2 of 4 - Confidence Interval for Proportions Questions4.0/ 4.0 PointsQuestion 8 of 20From a sample of 500 items, 30 were found to be defective. The point estimate of thepopulation proportion defective will be:
Feedback:30/500Question 9 of 20Page 4 of 12APUS CLE : MATH302 B005 Win 20 : Tests & Quizzes2/9/2020...
1.0/ 1.0 Pointsproportion of customers who click on ads on their smartphones to be (0.56 , 0.62). Select the correctanswer to interpret this interval1.0/ 1.0 PointsA random sample found that forty percent of 100 Americans were satisfied with the guncontrol laws in 2017. Compute a 99% confidence interval for the true proportion of Americans who weresatisfied with the gun control laws in 2017. Fill in the blanks appropriately.A 99% confidence interval for the true proportion of Americans who were satisfied with the gun controllaws in 2017 is ( 0.274 , 0.526 ) (Keep 3 decimal places)Suppose a marketing company computed a 94% confidence interval for the trueproportion of customers who click on ads on their smartphones to be (0.56 , 0.62). Select the correctanswer to interpret this intervalA.We are 94% confident that the true proportion of customers who click on ads on their smartphonesis between 0.56 and 0.62.B. 94% of customers click on ads on their smartphones.C.We are 94% confident that the true proportion of customers who click on ads on their smartphonesis 0.59.D.There is a 94% chance that the true proportion of customers who click on ads on their smartphonesis between 0.56 and 0.62.Answer Key:A
Question 10 of 20A random sample found that forty percent of 100 Americans were satisfied with the guncontrol laws in 2017. Compute a 99% confidence interval for the true proportion of Americans who weresatisfied with the gun control laws in 2017. Fill in the blanks appropriately.A 99% confidence interval for the true proportion of Americans who were satisfied with the gun controllaws in 2017 is ( 0.274 , 0.526 ) (Keep 3 decimal places)
Page 5 of 12APUS CLE : MATH302 B005 Win 20 : Tests & Quizzes