Question 6.Question :Two accounting professors decided to compare the variance of theirgrading procedures. To accomplish this, they each graded the same 10 exams, with the following results:At the 1% level of significance, what is the decision?
Student Answer:Reject the null hypothesis and conclude the variances are different. Fail to reject the null hypothesis and conclude the variances are different. Reject the null hypothesis and conclude the variances are the same. Fail to reject the null hypothesis and conclude the variances are the same. Instructor Explanation:The null hypothesis is . The computed value of F is found by taking the ratio of the two sample variances: . For the F ratio, , the degrees of freedom in both the numerator and the denominator are 9, found by n1- 1 and n2- 1, or 10 - 1. Using the "Critical values of the F distribution at a 1 percent level
of significance" table, the critical value of F with 9 degrees of freedom in the numerator, 9 degrees of freedom in the denominator, and the .01 significance level is 5.35. The computed value of 3.484 is less than the critical value of 5.35. Therefore, fail to reject the null hypothesis.
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Question 7.Question :Two accounting professors decided to compare the variance of theirgrading procedures. To accomplish this, they each graded the same 10 exams, with the following results:What is the null hypothesis?
Student
Answer:
Instructor
Explanation:
The null hypothesis is that the variance in the two populations is the same, .
Points Received:
0 of 1
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Question 8.Question :A large department store examined a sample of the 18 credit card sales and recorded the amounts charged for each of three types of credit cards: MasterCard, Visa, and Discover. Six MasterCard sales,seven Visa, and five Discover sales were recorded. The store used an ANOVA to test if the mean sales for each credit card were equal.
What are the degrees of freedom for the Fstatistic?
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1 of 1
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