Explain your prediction. Whenever the temperature falls too low or is raised too high, the enzyme will become denatured and lose its function. The more the temp is lowered or raised, the more the enzyme loses its structure so based on this information, lowering the temperature would cause the enzyme to denature and the rate of the activity to slow down. 6.) Design a controlled experiment to test the effect of varying pH, temperature, or enzyme concentration. Using the same substrate and catalase, to test the effect of different pH’s, researchers could use an experiment such as: 1- Perform a Base line assay to determine how much H 2 O 2 is initially in the solution 2- Take 11 beakers filled with 15mL of the H 2 O 2 solution. 3- Use one of the beakers as a basis for the experiment and take the pH of it. Time Intervals (s) 0-10 10-30 30-60 60-120 120-180 180-360 Rates .09 .045 .02 .01167 .0033 .00055
4- With 5 of the beakers of solution, add a 1mL of a weak acid to one of the beaker and continue with each of the 5 beakers, adding an additional drop (beaker 1=1mL, beaker 2=2mL, beaker 3=3mL….ect). 5- Take the other 5 beakers and do the same procedure but with a weak base 6- Measure the pH of all the beakers and record them in order from highest pH to lowest. 7- Add 1mL of the chilled catalase to each beaker, allow it to react for 15s, then add a high acid or base (depending on which beaker it is) to completely denature the enzyme and stop the reaction. 8- Perform a titration with KMnO 4 to determine how much H 2 O 2 was used. 9- The results of the experiment should be that the basis beaker contains the lowest amount of H 2 O 2 left because the optimal environment gives the most rapid reaction. As the pH becomes lower or higher from the basis, the enzyme become more denatured and thus the two beakers on the end should have the least H 2 O 2 used.
You've reached the end of your free preview.
Want to read all 6 pages?