2 01 ohm 0033 s 0005 s 25 v 5568 01 ohm 0184 s 0300 s

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100.2 0.1 ohm 0.033 s 0.005 s 2.5 V 556.8 0.1 ohm 0.184 s 0.300 s 2.5 V 547.9 0.1 ohm 0.180 s 0.029 s 2.5 V Would your measurements of have been different had you used a larger DC Voltage? In my opinion, changing the DC Voltage to a larger value of a DC Voltage would change our measurements of . The larger DC Voltage would result in higher resistance and therefore more electrical current can pass through. In addition, since tau in this experiment measures how fast the capacitor charges or discharges then that means the time it takes for the capacitors to charge/discharge would be faster compared to before because there is more current being stored in the electric field . 0 100 200 300 400 500 600 700 800 900 1000 0 0.01 0.02 0.03 0.04 0.05 0.06 Resistor (ohm) Tau (s) Measured Tau vs. Resistance for 330uF Capacitor
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0 100 200 300 400 500 600 700 800 900 1000 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 Resistance (ohm) Tau (s) Measured Tau vs Resistance for 100uF Capacitor What physical quantity does this slope correspond to and is its value what you expected? Slope = = .00009 The physical quantity of this slope seems to correspond to the capacitance/capacitor in the RC Circuit. In addition the slope, tau divided by the resistance, is the equation to calculate
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