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Part b is the reactant or product favored at

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Part BIs the reactant or product favored at equilibrium? (ThepKaof ethyloxidanium is2.4.)
2/5/2021Chapter 2 HomeworkCorrectEquilibrium favors the formation of the weaker acid because a stronger acid tends to donate its proton to the weaker acid. Hydrochloric acid(reactant) is a strong acid, and protonated ethyl alcohol or ethyloxidanium (product) is a weak acid, so the equilibrium will favor the product.Chapter 2 Problem 1Part AWhich of the followingis not a conjugate acid-base pair?-OH, O2-H2O, H3O+NO3-, NO2-H2O, HO-HSO4-, H2SO4
CorrectChapter 2 Problem 6Part AWhat is the conjugate acid of NH3?
CorrectChapter 2 Problem 3Part AThe conjugate acid of H2O is ________.
2/5/2021Chapter 2 HomeworkCorrectChapter 2 Problem 7Part AWhat is the conjugate acid of CH3NH2?ANSWER:CorrectChapter 2 Problem 8Part AWhat is the conjugate base of CH3NH2?+NH4+NH2-NH2-NH+NH3CH3NH3+NH2-CH3NH-NH4+
5/45CorrectChapter 2 Reading Question 1Part A
2/5/2021Chapter 2 HomeworkIdentify each of the species in the following reaction:Hint 1.Determining acids and bases and their conjugatesA base gains a proton (H+), forming its conjugate acid. An acid loses a proton, forming its conjugate base. See Section 2.1 (Page 51) .CorrectProblem 2.5Part AWhich is a stronger acid?CorrectPart BWhich is a stronger acid?CorrectChapter 2 Reading Question 2Part AThe pKaof CH3COOH is 4.8 and the pKaof CH3CH2OH is 15.9. Which of the following statements is correct?a

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