Neetor not perpendicular to normal vector hose

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NeetorNOTPerpendiculartonormalvector(hosedirectionVector[1,1,-1]notperpcndicdcrto[1,1/1]sincedotproduct=\noto
April193awcrKhanIntersectionzoizAssignment5)Firstplane![2,4/2]=[-21-7,5]+5[2/6,3]t*[1,4-1]A=[-4,-13,2]and13=[1,2/4]N,=AXBIUIbkz=[-56,18/5]'124IN,1=-0+8+52.=3/485=59,03ForSecondplane[X,-1,2)=[1,6,-2]tS[3,-2,5]t[5,4-6]G[-2,8,-3],D=[-3-3,11]iJKN2==}§-,3,=[74,28/22][email protected]€509lnlllnzl=86.65Cost[-56,18/5]×[74,28/22]=54.03X86.65COS0=381051149...0=41.850(050=0.7448
April19ZawcrkhcnIntersectionzoizAssignmentG)MustfirstfindtwootherpointonPlanewhen-2=02×-34=6-3×+51,=-6getx=6,4=12'.Point(6,130)WhenX=034+2=65-1+42=-6y=-3017i.2=1217point(0,-30/17,12/17)Setabevectorfrom(1,3,-1)to(6,12/0)A=[5,-9,1]Allowbvectorfrom(1,3,1)to(0,-301/17,12117)D=[1,21117,-24117]
April19ZawcrkhcnIntersectionzoizAssignmentGynormaltoplaneN=AxB=iJK-5-41\Ttz-=iE÷i¥s-;Ci5I÷)+ke¥)=(282/1,7)i-C162117)jt(48/17)KGeneralequationotplanersN.(X-Ko,Y-40,2-20)=O(282117,-162117,48/17).(Kt,yt3,2.1)to282(z-l)-1624+3)+48(2-1)=0282×-1624+482=25294×-544+162=8447×-274+8×-42.
April193awcrkhcnIntersectionzoizAssignmentGb)Sinceaxtby+C2=dgeneralequationofplanevectorparalleltothetheofintersectionthenisorthogonaltobothnormallineNi+Nzi.Planeparalleltothisvectorandvector[1,0/0]HasnormallaneOrthogonaltothisvectorOfintersectionandto51,0;D(UXNz)X[1,0/0]HavedirectionforplaneNeedtoEndPointonit[\,1,1[2,-1,-1]=[0,3,-3]pointindirectionoftheintersection[1,1/0]onlineofdntersectronG[0,3,-3]f+[1)1,0][0,3,-3]×[1,0,o][email protected],-3,-3]y-32=-3Simplifytoyt2=1
April19ZawcrKhanIntersectionzoizAssignmentFa)EqI=X3y-2-2+3=0Eq2=-Uktry+32-7=0Eq3=5×+44+2-5=0Eq3-Et1C5)0=(5×+44+2-5)-(5×-154-102+15)0=

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