6 Remove the 7kg weights one kg at a time Each time when one kg weight is

# 6 remove the 7kg weights one kg at a time each time

This preview shows page 1 - 5 out of 5 pages.

6. Remove the 7kg weights, one kg at a time. Each time when one kg weight is removed, adjust the micrometer screw to move the bubble back to the center of the level, and record the reading of the micrometer screw in data table 2. 7. Calculate the strain for each value of the stress in steps 5 and 6, and record the results in data table 1 and 2. 8. For each data table, plot a graph of stress vs strain and fit a straight line to the data. 9. Determine the slope of the straight line (Young’s Modulus) for both cases. Data Sheet L 1 = 341 mm L = 670 mm D = .00061m A = Π(D/2) 2 = 2.92 x 10 -7 m 2
Weight m (kg) Applied Force F = mg (N) Reading of the Micrometer Screw L 2 (mm) ΔL = L 2 -L 1 (mm) Strain ΔL/L Stress F/A (N/m 2 ) 1 9.8 346 5 .0075 3.36 x 10 7 2 19.6 360 19 .0284 6.71 x 10 7 3 29.4 369 28 .0418 1 x 10 8 4 39.2 379 38 .0567 1.34 x 10 8 5 49 388 47 .0701 1.68 x 10 8 6 58.8 402 61 .0910 2.01 x 10 8 7 68.6 414 73 .1090 2.35 x 10 8 Table 1 0 0.02 0.04 0.06 0.08 0.1 0.12 0 5 10 15 20 25 f(x) = 205.08x + 1.59 Stress vs Strain Strain Stress (x 10^7)
Weight m (kg) Applied Force F = mg (N) Reading of the Micrometer Screw L 2 (mm) ΔL = L 2 -L 1 (mm) Strain ΔL/L Stress F/A (N/m 2 ) 1 68.6 414 73 .1090 2.35 x 10 8 2 58.8 403 62 .0925 2.01 x 10 8 3 49 389 48 .0716 1.68 x 10 8 4 39.2 378 37 .0552 1.34 x 10 8 5 29.4 368 27 .0403 1 x 10 8 6 19.6 358 17 .0254 6.71 x 10 7 7 9.8 349 8 .0119 3.36 x 10 7 Table 2 Calculations Table 1 Calculations 0 0.02 0.04 0.06 0.08 0.1 0.12 0 5 10 15 20 25 f(x) = 204.88x + 1.53 Stress vs Strain Strain Stress (x10^7)
Discussion
1. When the elastic limit is not exceeded, the deformation is recoverable so comparing both cases of increasing and decreasing the hanging weights, the strain should be the same for the same stress.

#### You've reached the end of your free preview.

Want to read all 5 pages?

• Spring '17
• HalinaOprychal

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern