Cfr part 25 transport positive load factor limit

This preview shows 8 out of 13 pages.

CFR Part 25 (transport) Positive load factor limit, n_plus > 2.5 g Negative load factor limit, n_minus < -1 g (typical)
Image of page 8

Subscribe to view the full document.

9 MAE 2 V-n Diagram Load Factor Airspeed n = L W = 1 2 V 2 S / W C L , max n =− 1 2 V 2 S / W k L C L ,max n minus n plus n = 1 V corner V stall Positive limit load factor Negative limit load factor Maximum dive speed 0.6 k L 1.0 V corner = 2 n plus W / S C L ,max
Image of page 9
10 MAE 2 Lift Distributions The lift distribution specifies how aerodynamic lift is spread over the entire wing. L y = 4 L b 1 2y b 2 L y = 2 L b 1  [ 1 2y b 1 − ] L = nW = lift n = load factor W = weight c t = tip chord c r = rootchord = taper ratio = c t / c r Elliptical Wing: Trapezoidal Wing: Lift Distribution : L(y) y = spanwise location b = wingspan
Image of page 10

Subscribe to view the full document.

11 MAE 2 Stress and Strain A load (force) applied to a structural element causes stress in the material. = F A F = applied force A = cross section area = stress Compression: Tension: F F F F l ≡ l l Strain measures how the material reacts to applied loads. The modulus of elasticity defines a linear relationship between stress and strain. = E = strain E = Young ' s modulus of elasticity l length = l
Image of page 11
12 MAE 2 Shear Strain and Strain Shear acts tangentially to the cross-sectional area under load.
Image of page 12

Subscribe to view the full document.

Image of page 13
You've reached the end of this preview.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern