# Final velocity vf 2 xt vnot velocity v xt average

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the final velocity equation, the velocity equation, and the average acceleration equation. Final velocity: vf = (2) x/t - vnot Velocity: v = x/t Average Acceleration: a = vf – vnot / t

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Karyme Avina Jaime Munoz Summer O’Hara Alyssa Zavala Period. 6 Data: Trial 1 1 2 3 Height .11 m .07 m .15 m Time 1.45 s 1.84 s 1.04 s Average Time 1.44s Final Velocity 1.4 m/s 1.1 m/s 1.9 m/s Average Acceleration .97 m/s^2 .60 m/s^2 1.8 m/s^2 Trial 2 1 2 3 Distance 1 m 1.22 m .50 m Time 1.09 s 1.28 s 0.55 s Average Time 0.97 s Final Velocity 1.83 m/s 1.91 m/s 1.81 m/s Average Acceleration 1.68 m/s^2 1.49 m/s^2 3.29 m/s^2 Trial 3 1 2 3 Weight 99.6 g 599.6 g 119.7 g Time 1.09 s 1.40 s 1.16 s Average Time 1.21 s Final Velocity 1.83 m/s 1.43 m/s 1.72 m/s Average Acceleration 1.68 m/s^2 1.02 m/s^2 1.48 m/s^2 Data Calculations: Trial 1.1: Final velocity = (2)x / t – vnot ---- 2(1m)/ 1.45s = 1.4 m/s Average acceleration= vf – vnot / t ---- 1.4 m/s - 0 /1.45s = .97 m/s^2 Trial 1.2: Final velocity = (2)x / t – vnot ---- 2(1m)/1.84s= 1.1 m/s Average acceleration= vf – vnot / t----- 1.1 m/s - 0 / 1.84s= . 60 m/s^2 Trial 1.3: Final velocity = (2)x / t – vnot ---- 2(1m) / 1.04s = 1.9 m/s Average acceleration= vf – vnot / t----- 1.9 m/s - 0 / 1.04s= 1.8 m/s^2 Trial 2.1: Final velocity = (2)x / t – vnot ---- 2(1m)/ 1.09s = 1.83 m/s Average acceleration= vf – vnot / t-----
Karyme Avina Jaime Munoz Summer O’Hara Alyssa Zavala Period. 6 1.83 m/s - 0 / 1.09s = 1.68 m/s^2 Trial 2.2: Final velocity = (2)x / t – vnot ---- 2(1.22m) / 1.28s = 1.91 m/s Average acceleration= vf – vnot / t----- 1.91 m/s - 0 / 1.28s = 1.49 m/s^2 Trial 2.3: Final velocity = (2)x / t – vnot ---- 2(.50m) / .55s = 1.81 m/s Average acceleration= vf – vnot / t----- 1.81 m/s - 0 / .55s = 3.29 m/s^2 Trial 3.1: Final velocity = (2)x / t – vnot ---- 2(1m) / 1.09s = 1.83 m/s Average acceleration= vf – vnot / t----- 1.83 m/s - 0 / 1.09s = 1.68 m/s^2 Trial 3.2: Final velocity = (2)x / t – vnot ---- 2(1m) / 1.4s = 1.43 m/s Average acceleration= vf – vnot / t----- 1.43 m/s - 0 / 1.4s = 1.02 m/s^2 Trial 3.3: Final velocity = (2)x / t – vnot ---- 2(1m) / 1.16s = 1.72 m/s Average acceleration= vf – vnot / t----- 1.72 m/s - 0 / 1.16s = 1.48 m/s^2

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Karyme Avina Jaime Munoz Summer O’Hara Alyssa Zavala Period. 6 Graphs:
Karyme Avina Jaime Munoz Summer O’Hara Alyssa Zavala Period. 6 Discussion Questions: 1. Explain what allows the object to accelerate?

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• Fall '19
• Velocity, Jaime Munoz, Alyssa Zavala

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