Solution a E r V I Going counterclockwise around the loop using the loop rule

# Solution a e r v i going counterclockwise around the

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Solution (a) E r V I Going counterclockwise around the loop using the loop rule gives: A 10 58 . 1 A 10 5848 . 1 100 . 0 10 00 . 1 V 585 . 1 or 0, 3 3 3 r R E I IR Ir E
OpenStax College Physics Chapter 18-21 (b) The terminal voltage is given by the equation Ir E V : Note: The answer is reported to 5 significant figures to see the difference. V 5848 . 1 100 . 0 A 10 5848 . 1 V 585 . 1 3 Ir E V (c) To calculate their ratio, divide the terminal voltage by the emf: 0.99990 V 85 5 . 1 V 848 5 . 1 E V 9. (21.72) Using the exact exponential treatment, find how much time is required to discharge a μF - 250 capacitor through a - 500 resistor down to 1.00% of its original voltage. Solution s 576 . 0 .0100 0 ln s 125 . 0 ln and ; s 125 . 0 F 10 2.50 500 0 0 -4 V V τ t e V V RC τ τ -t

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• Fall '18
• Afrifa
• Electric charge, OpenStax College Physics

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