Question 15 of 20 10 10 points a university changed

• 26
• 95% (132) 126 out of 132 people found this document helpful

This preview shows page 18 - 21 out of 26 pages.

Question 15 of 20 1.0/ 1.0 Points A university changed to a new learning management system during the past school year. The school wants to find out how it’s working for the different departments – the results in preference found from a survey are below. Run a test for independence at α=0.05 Prefers Old LMS Prefers New LMS No Preference School of Business 18 29 8 School of Science 41 11 4 School of Liberal Arts 25 20 7 After running an independence test, can it be concluded that preference in learning management system is dependent on department? . A. Yes, it can be concluded that preference in learning management system is dependent on department because the p-value = 0.0017 B.
Yes, it can be concluded that preference in learning management system is dependent on department because the p-value = 0.00085 C. No, it cannot be concluded that preference in learning management system is dependent on department because the p-value = 0.00085 D. No, it cannot be concluded that preference in learning management system is dependent on department because the p-value = 0.0017 Answer Key:B Feedback: We are running a Chi-Square Test for Independence. Copy and Paste the table into Excel. You are given the Observed Counts in the table. We need to calculate the Expected Counts. Then sum up the rows and column. You need to find the probability of the row and then multiple it by the column total. Prefers Old LMS Prefers New LMS No Preference Sum School of Business 18 29 8 55 School of Science 41 11 4 56 School of Liberal Arts 25 20 7 52 Sum 84 60 19 163 Prefers Old LMS Prefers New LMS No Preference School of Business =84*(55/163) =60*(55/163) =19*(55/163) School of Science =84*(56/163) =60*(56/163) =19*(56/163) School of Liberal Arts =84*(52/163) =60*(52/163) =19*(52/163) Now that we calculated the Expected Count we can use Excel to find the p-value. Use =CHISQ.TEST(highlight actual counts, highlight expected counts) = 0.00085
Question 16 of 20 1.0/ 1.0 Points Click to see additional instructions A high school runs a survey asking students if they participate in sports. The results are found below. Run an independence test for the data at α=0.01 Freshmen Sophomores Juniors Seniors Yes 75 88 55 42 No 30 28 38 40 Enter the P -Value - round to 4 decimal places. Make sure you put a 0 in front of the decimal. 0.0010 .