Question 28 2 use source transformation to determine

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Question 2.8 [2] Use source transformation to determine v s .
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EBN111 2014-Exam 16 Vraag 2.9 [2] Bepaal die bydrae van die 5m A spanningsbron tot v y . Question 2.9 [2] Calculate the contribution of 5m A source to v y .
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EBN111 2014-Exam 17 Vraag 2.10 [4] Bepaal die Thevenin ekwivalent V TH en R TH met betrekking tot terminale a-b . Question 2.10 [4] Determine the Thevenin equivalent V TH and R TH with respect to terminals a - b .
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EBN111 2014-Exam 18 Vraag 2.11 [4] Bepaal die Norton ekwivalent I N en R N met betrekking tot terminale las R . Question 2.11 [4] Determine the Norton equivalent current I N and resistance R N with respect to load R . uni0035uni0030uni03A9 uni0035uni0030uni03A9 uni0035uni0030uni03A9 uni0035uni0030uni03A9 uni0034uni0030uni0030uni0056 uni002B uni002D uni0052 uni0035uni0030uni03A9 uni0035uni0030uni03A9 uni0032uni002Euni0035uni0041
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EBN111 2014-Exam 19 VRAAG/QUESTION 3 [17] Vraag 3.1 [2] Bepaal v o en i o . Question 3.1 [2] Determine v o and i o .
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EBN111 2014-Exam 20 Vraag 3.2 [3] a) Watter waarde vir die terugvoer weerstand, R f , sal veroorsaak dat die op-amp negatief versadig (-15 v o 15) indien v s =3V? b) Wanneer v s = 12V en R f = 2 k Ω , bepaal die stroom i o en die spanning v o . Question 3.2 [3] a) What value of feedback resistance, R f , will negatively saturate (-15 v o 15) the op amp, given v s =3V? b) When v s =12V and R f = 2k Ω calculate the current i o and voltage v o . uni002Buni0031uni0035uni0056 uni002Duni0031uni0035uni0056 uni0036uni006Buni03A9 uni0031uni006Buni03A9 v s uni0034uni006Duni0041 + v o - uni0052 uni0066 uni0038uni006Buni03A9 i o + -
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EBN111 2014-Exam 21 Vraag 3.3 [3] a) Gegee: R1 = 1 k Ω , R2 = 2 k Ω . Bepaal v o . b) Watter waarde van R1 en R2 sal hierdie verskil versterker verander na ‘n kringbaan waar g1874 g3042 =g1874 g2870 −g1874 g2869 ? Question 3.3 [3] a) Given R1 = 1 k Ω , R2 = 2 k Ω . Find v o . b) What value of R1 and R2 will change this difference amplifier into a subtractor ( g1874 g3042 =g1874 g2870 −g1874 g2869 )?
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EBN111 2014-Exam 22 Vraag 3.4 [3] Dit word gegee dat v in = –2m V. Bepaal v 1 , v 2 en v o Question 3.4 [3] It is given that v in = –2m V. Calculate v 1 , v 2 and v o
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EBN111 2014-Exam 23 Vraag 3.5 [2] Aanvaar gelykstroom toestande in die kringbaan. Bepaal die totale energie gestoor in die induktors ( w L ) en in die kapasitors ( w C ). Question 3.5 [2] Assume direct current conditions in the circuit. Determine the total energy stored in the inductors ( w L ) and the capacitors ( w C ).
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EBN111 2014-Exam 24 Vraag 3.6 [4] By t=0.1 s bepaal die spanning oor die: a) kapasitors, v C in figuur (a). Aanvaar v c (0) = 0. Gee die antwoord in m V. b) induktors v L in figuur (b). Gee die antwoord in μ V. Question 3.6 [4] At t=0.1 s, determine the voltage across the: a) capacitors, v C in figure (a). Assume v c (0) = 0. Give the answer in m V. b) inductors v L in figure (b). Give the answer in μ V.
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EBN111 2014-Exam 25 VRAAG/QUESTION 4 [20] Vraag 4.1 [4] g1874 g2869 =−10cosg466610g1872−30°g4667g1848 g1874 g2870 =10sing466610g1872+120°g4667g1848 a) Bepaal g1874 g2868 =g1874 g2869 +g1874 g2870 en skryf die finale antwoord in die vorm g1827cosg4666g2033g1872+g2038g4667 waar g1827>0 en −180°< g2038<180° .
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  • Spring '13
  • Bhatt

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