.
rad / s
rad / s
s.
2
4. P.10.37. We use the parallel axis theorem:
I = I
com
+
Mh
2
, where
I
com
is the rotational inertia
about the center of mass (see Table 10-2(d)),
M
is the mass, and
h
is the distance between the
center of mass and the chosen rotation axis. The center of mass is at the center of the meter stick,
which implies
h
= 0.50 m – 0.20 m = 0.30 m. We find
(
)(
)
2
2
2
com
1
1
0.56 kg
1.0 m
4.67
10
kg m .
12
12
I
ML
−
=
=
=
×
⋅
2
Consequently, the parallel axis theorem yields
(
)(
)
2
2
2
2
2
4.67
10
kg m
0.56 kg
0.30 m
9.7
10
kg m .
I
−
−
=
×
⋅
+
=
×
⋅
5. P.10.39. The particles are treated
“point-like”
in the sense that Eq. 10-33 yields their rotational
inertia, and the rotational inertia for the rods is figured using Table 10-2(e) and the parallel-axis
theorem (Eq. 10-36).
(a) With subscript 1 standing for the rod nearest the axis and 4 for the particle farthest from it,
we have

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