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CHE 243: Engineering ThermodynamicsState 3: As the water continues to cool, the stops prevent the piston from moving further, so the volume remains constant. Since the mass and volume of the system do not change, v3 = v2. The phase of the water in state 3 is saturated mixture.(2)The overall change in internal energy can be found using the following equation:∆𝑈1→3= 𝑚(𝑢3− 𝑢1)(1)Note that it is not necessary to determine the internal energy in state 2 to solve the problem.The required values are u1(initial state) and u3(final state). u1can be directly found on table A-6 (Superheated vapor at 200 kPa and 200 ºC).
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