# The denominator will halve in value the denominator

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10/18/2019Lab 3 - Newton's Second Law: PostLab7/14(b) Consider the situation when friction force is non-zero. What is the expression for the acceleration of the cart now? (Use thefollowing as necessary: m1, m2, f, and g.)
If you now halve the hanging mass m1, (so m= 0.5m1) how will the value of the denominator for the expression for the accelerationchange?What is the expression for the acceleration now? (Use the following as necessary: m1, m2, f, and g.)
10/18/2019Lab 3 - Newton's Second Law: PostLab8/14Based on your answers to the previous parts, what conclusion can you draw about the acceleration of the cart?Additional MaterialsNewton's Second LawAppendixThe cart's acceleration will halve as the numerator in the expression for the acceleration will halve when m1is halved.The cart's acceleration will remain the same as the total mass is constant during the experiment. The acceleration will increase by a certain value but not by a factor of ½.
10/18/2019Lab 3 - Newton's Second Law: PostLab9/144.10/10 points | Previous AnswersIn the diagram below, indicates the pulling force and the friction force acting on the object. The direction of motion of the object isindicated by the velocity vector .Figure AFigure BFigure CFor each case, indicate the direction of the net force, the direction of the acceleration of the object and state whether the object is speedingup, slowing down, or moving with constant velocity. The force vectors are drawn to scale.Direction of net forceDirection of accelerationThe object isAto the left to the leftto the left to the leftslowing down slowing downBto the right to the rightto the right to the rightspeeding up speeding upCThe net force is zero.