Substance atom oxidation state naf na 1 1 al 2 o 3 o

Info icon This preview shows pages 2–5. Sign up to view the full content.

View Full Document Right Arrow Icon
substance atom oxidation state NaF Na +1 +1 Al 2 O 3 O -2 -2 H 3 PO 4 P +5 +5 ClO 4 1- Cl +7 +7 . 3. 0.25/0.25 points | 1/5 submissions No Marks. To determine what portion of the question you have correct, click on question score at the top of the assignment. Be sure to refresh question score after each submission. Rate the following bonds to oxygen in order of increasing polarity. Use numbers 1-4 with 1 = least polar and 4 = most polar. (Hint: Refer to a Table of Electronegativities (Table 5.1 in text) and calculate the electronegativity differences.) O-H 4 4 O-F 3 3 O-Br 1 1 O-N 2 2 4. 0.25/0.25 points | 2/5 submissions No Marks. To determine what portion of the question you have correct, click on question score at the top of the assignment. Be sure to refresh question score after each submission. Bonus/Replacement HW#2 ... 2 of 10 12/14/08 3:06 AM
Image of page 2

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Use the orbital diagram of atoms X and Z below to answer the following questions. The input format is +# or -# for oxidation states. a) What is the most common oxidation state of X when bound to Z? +3 3 b) What is the most common oxidation state of Z when bound to X? -2 -2 c) If X is a period 3 metal what element does it represent? Type in the chemical symbol (without any charge). Al Al d) If Z is a period 2 non-metal, what element does it represent? Type in the chemical symbol (without any charge). O O e) Using the charges from questions a and b above, and the chemical symbols from questions c and d above, what is the chemical formula for a neutral compound of X and Z in their most common oxidation states? Be sure to put the most electronegative atom last. Al2O3 Al2O3 5. 0.25/0.25 points | 1/5 submissions No Marks. To determine what portion of the question you have correct, click on question score at the top of the assignment. Be sure to refresh question score after each submission. Select the appropriate name or chemical formula for the compounds below. CF 4 carbon pentafluoride carbon tetrafluoride carbon(IV) fluoride carbon(IV) tetrafluoride RhCl 3 rhodium(III) trichloride rhodium(III) chloride rhodium chloride rhodium trichloride magnesium selenide Mg 2 Se MgSeO 3 MgSe MgSe 2 6. 0.25/0.25 points | 1/5 submissions Bonus/Replacement HW#2 ... 3 of 10 12/14/08 3:06 AM
Image of page 3
No Marks. To determine what portion of the question you have correct, click on question score at the top of the assignment. Be sure to refresh question score after each submission. Using only the position of the atoms on the periodic table , determine the correct order for ranking the bonds according to increasing polarity. Do NOT use a table of electronegatitives to generate your answer. Sometimes the two answers do not agree.
Image of page 4

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 5
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern