a.a)Area (rect) = 110 x 50 = 5500cm*2b.Area (trap) = (110 + 180) (140 – 50)/2 =13050cm*2c.Area (total) = 5500 cm*2 + 13050cm*2d.Area (total) = 18550 cm*2e.f.DE = 10*2 – 8*2ADE = 8 x 6/2g.DE = 100 – 64ADE = 24 fh.DE = 36 = 6 fi.j.k.l.m.n.o.Area ABCE = 8 x 8 = 64 fp.Area (total) = 24 + 64q.= 88 f*2r.s.
10.Find the measure of both arc AB and arc APB, where <APB = 108◦. Please be sure to show your steps.
a.b.c.Art AB is the double of angle APBd.Arc AB = 2e.≤APB = 2 x 108f.≤APB = 216g.h.The measure of arc APB is the difference of 360’i.So, 360 – 216 = 144’j.

Geometry Quarter ExamName: Jason Santos Student Number: JM 1707391Answer the questions below. Make sure to show your work and provide complete geometric explanations for fullcredit.
11.Find the area of a regular Octagon with side lengths 5 in. Round your answer to the nearest tenth.
o.12.Find the surface area of each figure to the nearest tenth. a.b.b. c.d.a). SA = 2 r h e.SA = 2 TT (5cm) (10cm)f.SA = 100 x TT cm*2g.SA = 100 x 3.14 cm*2h.SA = 314.16 cm*2

Geometry Quarter ExamName: Jason Santos Student Number: JM 1707391Answer the questions below. Make sure to show your work and provide complete geometric explanations for fullcredit.i.b). SA = (a + b + c) hj.SA = (4m + 2.5m + 2.5m) 6mk.SA = 54 m*2l.m.What is a real-world example or use of surface area?n.An example of the real world that we can use the surface area is in houses and buildings,we can also use surface area in a box.o.p.q.r.s.
13.Find the surface area of each figure to the nearest tenth.

Geometry Quarter ExamName: Jason Santos Student Number: JM 1707391Answer the questions below. Make sure to show your work and provide complete geometric explanations for fullcredit.

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