Solutions to Written Assignment 10_11_29_2017.pdf

2 1 03048 2 082 ℎ2 44 2 2 082 2824 2315 therefore

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𝑟2 = ? 𝑟1 = 0.3048 𝑇 𝑟2 = 0.82 → ? ℎ2 ≅ 4.4 𝑇 2 = 𝑇 𝑟2 ∗ 𝑇 𝐶𝑟 = 0.82 ∗ 282.4? = 231.5 ? Therefore: 2 − ℎ 1 = 1.548 𝑘? 𝑘𝑔 ∗ ? (231.5 − 260.15)? − 0.2964 𝑘? 𝑘𝑔 ∗ ? ∗ 282.4 ?(4.4 − 0.42) = −377.489 𝑘? 𝑘𝑔 ? = 10 𝑘𝑔 (−377.489 𝑘? 𝑘𝑔 ) = −3774.89 𝑘? As Q is negative, this indicates that heat flows out of the system. 3774.9 kJ of heat flows out of the Piston-Cylinder Device
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