since the slope of the line segment between (0, 0) and (2, 4) issince the slope of the line segment between (−2, 4) and (2, 0) isNow(b)sof(1) = 2g(1) = 1f'(1) = 2= 2;g'(1) =−14−02=−1.0−42−(−2)u(x) =f(x)g(u'(1) =f(1)g'(1) +g(1)f'(1) = 2·(−1) + 1·2 = 0.v(x) =f(x)/g(x),v'(5) ==g(5)f'(5)−f(5)g'(5)[g(5)]22−−221323==−48323so−0x),3·−
18.9/9 points |Previous AnswersIn this problem, consider the curvey=f(x)=11 +.(a) The derivative functionf ' (x) =(b) Find the point P=(a,f(a)) on the graph where the tangent line at P hasy-intercept 1/2:√x).
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