Since the slope of the line segment between 0 0 and 2

since the slope of the line segment between (0, 0) and (2, 4) is
since the slope of the line segment between ( − 2, 4) and (2, 0) is Now
(b) so
f (1) = 2 g (1) = 1
f ' (1) = 2 = 2; g' (1) = − 1
4 − 0
2
= − 1.
0 − 4
2 − ( − 2)
u ( x ) = f ( x ) g (
u' (1) = f (1) g' (1) + g (1) f ' (1) = 2
·
( − 1) + 1
·
2 = 0.
v ( x ) = f ( x )/ g ( x ), v' (5) = =
g (5) f ' (5) − f (5) g' (5)
[ g (5)]
2
2 − −
2
2
1
3
2
3 = = −
4
8
3
2
3
so
− 0
x ),
3
·
−
18. 9/9 points | Previous Answers
In this problem, consider the curve
y=f(x)=
1
1 +
.
(a) The derivative function f ' (x) =
(b) Find the point P=(a,f(a)) on the graph where the tangent line at P has y -intercept 1/2:
√
x
).