For Organization D we establish a starting IP address by taking the binary of

For organization d we establish a starting ip address

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For Organization D, we establish a starting IP address by taking the binary of the last IP address used for Organization C and using the first bit that was not used as a host for Organization C. This would be the 15th bit from the right. Therefore, we can establish the binary representation of the starting IP address for Organization D as: 11000110 00010000 01000000 00000000 This is represented in decimal as: 198.16.64.0 Organization D is requesting 8000 addresses, so the nearest power of 2 value would be 13 (8192). We now take our above starting address and convert host bits to display our last IP address for Organization D as follows (binary): 11000110 00010000 01011111 11111111 We now convert this to decimal: 11000110 = 198 00010000 = 16 01011111 = 95 11111111 = 255 Therefore, our last IP address for Organization B is:
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CS 2204: UNIT 5 WRITTEN ASSIGNMENT 16 198.16.95.255 and since we used 13 host bits our mask will be (32-13): 198.16.64.0/19 Q3. A router R has the following distance-vector table: Destination Cost Next hop A 2 R1 B 3 R2 C 4 R1 D 5 R3 R now receives the following report from R1 (the cost of the R–R1 link is 1): <dest: A, cost: 1>, <dest: B, cost: 1>, <dest: C, cost: 4>, <dest: D, cost: 4>. Give R’s updated table after it processes R1’s report. For each entry, give a brief explanation. For Destination A and C, R1 factors in per Next hop. For Destination B and C, next hop is not R1. Therefore, based on this and R-R1 link is 1:
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CS 2204: UNIT 5 WRITTEN ASSIGNMENT 17 After processing R1 report the table updates to: Destination A Cost (2+1) = 3 Destination B Cost (no change)=3 Destination C Cost (4+1)=5 Destination D Cost (no change)=5 References Dordal, P. (2014). An Introduction to Computer Networks . This book is licensed under Creative Commons Attribution-NonCommerical-NoDerivs 3.0 Unported (CC BY-NC-ND 3.0). Retrieved from sText.pdf
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