Mass And Mole Relationships In A Chemical Equation Notes

Theory the data collected in this experiment included

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Theory The data collected in this experiment included the mass of NaHCO 3 , the mass of NaCl, and the moles of NaCO 3 . The mass and moles of NaHCO 3 were found so that when the mass of the NaCl was produced, percent yield could be calculated. A chemical reaction that occurred was the mixture and heating of NaHCO 3 and hydrochloric acid. The relationship between the mass and moles of a substance is very close. This formula was used to determine the number of moles in a substance. Moles of NaHCO 3 : MM=m/n Where MM= molar mass of a substance in grams/mole Where m= mass of a substance in grams Where n= number of moles in a substance Materials Equipment: 1. Evaporating dish 2. Watch glass
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3. Pipet 4. 10 mL graduated cylinder 5. Bunsen burner 6. Wire gauze 7. Electric scale Chemicals: 1. Sodium Bicarbonate 2. Hydrochloric acid Procedures 1. Place the evaporating dish system (evaporating dish and watch glass) on a wire gauze. 2. Using a Bunsen burner, heat the evaporating dish system on a low flame for 3 to 5 minutes. 3. Pour about 0.5 g of sodium bicarbonate into the evaporating dish system. 4. Pour 16 mL of a 0.5 M hydrochloric acid solution into the evaporating dish system. 5. Place the evaporating dish system on the wire gauze and heat until the solution has dried. Data This data was found in order to investigate mass and mole relationships. Mass of Empty Evaporating Dish System 97.7 Mass of Evaporating Dish System and NaHCO 3 98.2 Mass of NaHCO 3 0.500 Moles of NaHCO 3 0.00600 Theoretical Mass of NaCl 0.350 Mass of Evaporating Dish System and NaCl 98.0 Mass of NaCl 0.300 Percent Yield 86% Calculations
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